java 如何使用bufferedreader在java中接受字符串数组

how to accept string array in java using bufferedreader

提问by Yash Srivastava

public static void accept_name( String[] name, int[] r)
{

   InputStreamReader isr = new InputStreamReader(System.in);
   BufferedReader ab = new BufferedReader(isr);
    r = new int[40];
    name = new String[40];
    for(int i=0;i<40;i++)
    {
        System.out.println("Enter the name of students");
        name[i] = ab.readLine();
    }             
}

i am having a problem in name[i] = ab.readLine();

我在 name[i] = ab.readLine() 中遇到问题；

i don't understand what the problem is.

我不明白问题是什么。

采纳答案by Khaled.K

When using Input\Output stream, an IOExceptionis expected, define that it might throw that kind of exception:

使用 Input\Output 流时，需要IOException定义它可能会抛出那种异常：

public static void accept_name (String[] name, int[] r) throws IOException
{
   InputStreamReader isr = new InputStreamReader(System.in);
   BufferedReader ab = new BufferedReader(isr);

    r = new int[40];
    name = new String[40];

    for(int i=0;i<40;i++)
    {
        System.out.println("Enter the name of students");
        name[i] = ab.readLine();
    }             
}

回答by Suresh Atta

Actually,If you mouseover on the error line ,the message there tells everything.

实际上，如果您将鼠标悬停在错误行上，则那里的消息会说明一切。

It's a compile time error.Asking for exceptionhandling.While executing that line there are chances to get the IOException.

这是一个编译时错误。要求exception处理。执行该行时，有机会获得IOException.

So you have to handleit by throwing in the methodsignature or by catching it there itself.

因此，您必须handle通过输入method签名或将其捕获在那里来实现它。

Change your method to

将您的方法更改为

public static void accept_name( String[] name, int[] r)
    {

       InputStreamReader isr = new InputStreamReader(System.in);
       BufferedReader ab = new BufferedReader(isr);
        r = new int[40];
        name = new String[40];
        for(int i=0;i<40;i++)
        {
            System.out.println("Enter the name of students");
            try {
                name[i] = ab.readLine();
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }             
    }

Heavily recommending concept

强烈推荐概念

回答by Aniket Thakur

You are getting name array in the function argument why are you initializing it again? Below is not required

您在函数参数中获取名称数组，为什么要再次初始化它？以下不需要

name = new String[40];
r = new int[40];

You code must be

你的代码必须是

public static void accept_name( String[] name, int[] r)
{

   InputStreamReader isr = new InputStreamReader(System.in);
   BufferedReader ab = new BufferedReader(isr);
    for(int i=0;i<40;i++)
    {
        System.out.println("Enter the name of students");
        try {
            name[i] = ab.readLine();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }             
}

and then you can call your function as

然后你可以调用你的函数

String[] name = new String[40];
//populate your name array
int[] r = new int[40];
//populate your r array
ClassName.accept_name(name,r);//Static function

also I don't see where you are using r.

我也没有看到你在哪里使用 r。

回答by Carlo Bertuccini

Readline throws an IOException so you should catch it or rethrow.

Readline 会抛出一个 IOException，因此您应该捕获它或重新抛出。

public static void accept_name(String[] name, int[] r) throws IOException {
 [...]
}

Carlo

卡罗

回答by NULL

You could try this...

你可以试试这个...

    public static void accept_name( String[] name, int[] r)
    {

       name = new String[40];
       for(int i=0;i<40;i++)
       {
            try {
                  InputStreamReader isr = new InputStreamReader(System.in);
                  BufferedReader ab = new BufferedReader(isr);
                  System.out.println("Enter the name of students");
                  name[i] = ab.readLine();
                  ab.close();
            } catch (IOException e) {
                  e.printStackTrace();
            }
       }             
    }