php 资源控制器的 Laravel 命名路由

Laravel named route for resource controller

提问by flyingL123

Using Laravel 4.2, is it possible to assign a name to a resource controller route? My route is defined as follows:

使用 Laravel 4.2，是否可以为资源控制器路由分配名称？我的路线定义如下：

Route::resource('faq', 'ProductFaqController');

I tried adding a name option to the route like this:

我尝试向路线添加名称选项，如下所示：

Route::resource('faq', 'ProductFaqController', array("as"=>"faq"));

However, when I hit the /faq route and place {{ Route::currentRouteName() }}in my view, it yields faq.faq.indexinstead of just faq.

但是，当我点击 /faq 路线并放置{{ Route::currentRouteName() }}在我的视图中时，它会产生faq.faq.index而不仅仅是faq.

回答by Aken Roberts

When you use a resource controller route, it automatically generates names for each individual route that it creates. Route::resource()is basically a helper method that then generates individual routes for you, rather than you needing to define each route manually.

当您使用资源控制器路由时，它会自动为它创建的每个单独路由生成名称。Route::resource()基本上是一个辅助方法，然后为您生成单独的路由，而不是您需要手动定义每个路由。

You can view the route names generated by typing php artisan routesin Laravel 4 or php artisan route:listin Laravel 5 into your terminal/console. You can also see the types of route names generated on the resource controller docs page (Laravel 4.x| Laravel 5.x).

您可以查看通过php artisan routes在php artisan route:list终端/控制台中输入Laravel 4 或Laravel 5生成的路由名称。您还可以在资源控制器文档页面 ( Laravel 4.x| Laravel 5.x)上查看生成的路由名称类型。

There are two ways you can modify the route names generated by a resource controller:

有两种方法可以修改资源控制器生成的路由名称：

1. Supply a namesarray as part of the third parameter $optionsarray, with each key being the resource controller method (index, store, edit, etc.), and the value being the name you want to give the route.

   Route::resource('faq', 'ProductFaqController', [
       'names' => [
           'index' => 'faq',
           'store' => 'faq.new',
           // etc...
       ]
   ]);
   

2. Specify the asoption to define a prefix for every route name.

   Route::resource('faq', 'ProductFaqController', [
       'as' => 'prefix'
   ]);
   

   This will give you routes such as prefix.faq.index, prefix.faq.store, etc.

1. 提供一个names数组作为第三个参数$options数组的一部分，每个键是资源控制器方法（索引、存储、编辑等），值是您要为路由指定的名称。

   Route::resource('faq', 'ProductFaqController', [
       'names' => [
           'index' => 'faq',
           'store' => 'faq.new',
           // etc...
       ]
   ]);
   

2. 指定as为每个路由名称定义前缀的选项。

   Route::resource('faq', 'ProductFaqController', [
       'as' => 'prefix'
   ]);
   

   这会给你的路线，例如prefix.faq.index，prefix.faq.store等等。

回答by Marc

For answer seekers with Laravel 5.5+ finding this page:

对于使用 Laravel 5.5+ 查找此页面的答案寻求者：

Route::namespace('Admin')->prefix('admin')->name('admin.')->group(function () {

    Route::resource('users','UserController');

});

These options will result in the following for the Resource:

这些选项将为Resource产生以下结果：

• namespace()sets Controller namespace to \Admin\UserController

• prefix()sets request URi to /admin/users

• name()sets route name accessor to route('admin.users.index')

• namespace()将控制器命名空间设置为 \Admin\UserController

• prefix()将请求 URI 设置为 /admin/users

• name()将路由名称访问器设置为 route('admin.users.index')

In name()the DOT is intended, it is not a typo.

在name()DOT 中，它不是一个错字。

Please let others know if this works in comments for any versions prior to Laravel 5.5, I will update my answer.

请让其他人知道这是否适用于 Laravel 5.5 之前的任何版本的评论，我会更新我的答案。

Update:

更新：

I can confirm that in Laravel 5.3that the namemethod is not available. No confirmation yet if supported in 5.4

我可以确认在 Laravel 5.3中该name方法不可用。如果5.4支持还没有确认

Taylor accepted my PR to officially document this in 5.5:

Taylor 接受了我的 PR 在 5.5 中正式记录了这一点：

https://laravel.com/docs/5.5/routing#route-group-name-prefixes

https://laravel.com/docs/5.5/routing#route-group-name-prefixes

回答by Hamidreza

I don't know if it's available in laravel 4.2 (I tested in 5.7) but you can use namesto change the name of all routes generated by resource

我不知道它在 laravel 4.2 中是否可用（我在 5.7 中测试过）但您可以使用它names来更改资源生成的所有路由的名称

Route::resource('faq', 'ProductFaqController', ['names' => 'something']);

and the result will be like this

结果会是这样

something.index

and you don't need to specify each route

并且您不需要指定每条路线

回答by Brayan Angarita

Using Laravel 5.5

使用 Laravel 5.5

Route::resource('admin/posts/tags', 'PostTagController', ['as' => 'posts']);

Route::resource('admin/posts/tags', 'PostTagController', ['as' => 'posts']);

important to keep in mind the "resource"

重要的是要记住“资源”

For example, I send something from my project:

例如，我从我的项目中发送了一些东西：

Route::resource('admin/posts/tags', 'PostTagController', ['as' => 'posts']);

回答by Uzair

All Updates Later then Laravel 5.5 Using

Laravel 5.5 之后的所有更新使用

Route::resource('faqs', 'FaqController', ['as' => 'faqs']);

if we not use ['as' => 'faqs']in above code then it will also work same.

如果我们不在['as' => 'faqs']上面的代码中使用，那么它也将工作相同。

[Updated]

[更新]

Important to keep in mind that this will work for "resource"

重要的是要记住，这将适用于“资源”

For example:

例如：

Route::resource('admin/posts/tags', 'PostTagController', ['as' => 'posts']);

and result will be like

结果会像

 POST      | admin/posts/tags                  | posts.tags.store
 GET|HEAD  | admin/posts/tags                  | posts.tags.index
 GET|HEAD  | admin/posts/tags/create           | posts.tags.create
 DELETE    | admin/posts/tags/{tag}            | posts.tags.destroy
 PUT|PATCH | admin/posts/tags/{tag}            | posts.tags.update
 GET|HEAD  | admin/posts/tags/{tag}            | posts.tags.show
 GET|HEAD  | admin/posts/tags/{tag}/edit       | posts.tags.edit

回答by Omid Ahmadyani

you dont need to set name in resource in laravel 5.7 that i have test it. it auto generate route name from url.

您不需要在我测试过的 laravel 5.7 中的资源中设置名称。它从 url 自动生成路由名称。