javascript 传递一个函数作为参数，然后在jquery函数中执行
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pass a function as a parameter and then execute it in a jquery function
提问by bobighorus
I was wondering which is the way to make this simple (and maybe stupid) thing with jQuery.
我想知道用 jQuery 使这个简单（甚至可能是愚蠢的）事情的方法是什么。
I have a function like this:
我有一个这样的功能：
function setSomething() {
make some stuff;
}
and then another function like this:
然后是另一个像这样的函数：
generalFunction(par1, par2, par3) {
do other stuff;
execute function called in par3;
}
Well, if I write something like this it doesn't work:
好吧，如果我写这样的东西是行不通的：
c=setSomething();
generalFunction(a, b, c);
So what's the way to call a function as a parameter of another function and then execute it inside?
那么有什么方法可以把一个函数作为另一个函数的参数调用，然后在里面执行呢？
I hope I was clear enough.
我希望我说得够清楚了。
Any help will be appreciated.
任何帮助将不胜感激。
Thank you in advance for your attention.
预先感谢您的关注。
回答by Willem D'Haeseleer
leave out the parentheses , you can then call the parameter as a function inside your "generalFunction" function.
省略括号，然后您可以将参数作为“generalFunction”函数内的函数调用。
setSomething(){
// do other stuff
}
generalFunction(par1, par2, par3) {
// do stuff...
// you can call the argument as if it where a function ( because it is !)
par3();
}
generalFunction(a, b, setSomething);
回答by JakeRHill
Here is another example for those who want to pass a parameter to a function that is passed in as a call back:
对于那些想要将参数传递给作为回调传入的函数的人，这是另一个示例：
$(document).ready(function() {
main();
});
function main() {
alert('This is the main function');
firstCallBack(1, 2, 3, secondCallBack);
};
function firstCallBack(first, second, third, fourth) {
alert('1st call back.');
var dataToPass = first + ' | ' + second;
fourth(dataToPass);
};
function secondCallBack(data) {
alert('2nd call back - Here is the data: ' + data)
};
Here is the JSFiddle link: https://fiddle.jshell.net/8npxzycm/
这是 JSFiddle 链接：https://fiddle.jshell.net/8npxzycm/
