用 JavaScript 计算时差
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Calculate Time Difference with JavaScript
提问by user1424332
I have two HTML input boxes, that need to calculate the time difference in JavaScript onBlur (since I need it in real time) and insert the result to new input box.
我有两个 HTML 输入框，需要计算 JavaScript onBlur 中的时间差（因为我需要实时）并将结果插入到新的输入框中。
Format example: 10:00 & 12:30 need to give me: 02:30
格式示例：10:00 & 12:30 需要给我：02:30
Thanks!
谢谢！
回答by VisioN
Here is one possible solution:
这是一种可能的解决方案：
function diff(start, end) {
start = start.split(":");
end = end.split(":");
var startDate = new Date(0, 0, 0, start[0], start[1], 0);
var endDate = new Date(0, 0, 0, end[0], end[1], 0);
var diff = endDate.getTime() - startDate.getTime();
var hours = Math.floor(diff / 1000 / 60 / 60);
diff -= hours * 1000 * 60 * 60;
var minutes = Math.floor(diff / 1000 / 60);
// If using time pickers with 24 hours format, add the below line get exact hours
if (hours < 0)
hours = hours + 24;
return (hours <= 9 ? "0" : "") + hours + ":" + (minutes <= 9 ? "0" : "") + minutes;
}
回答by Germo
Well this work almost great. Now use this code to calculate: 23:50 - 00:10 And see what you get.Or even 23:30 - 01:30. That's a mess. Because getting the answer the other way in php is:
好吧，这项工作几乎很棒。现在使用此代码计算： 23:50 - 00:10 看看你得到了什么。甚至 23:30 - 01:30。那是一团糟。因为在 php 中以另一种方式获得答案是：
$date1 = strtotime($_POST['started']);
$date2 = strtotime($_POST['ended']);
$interval = $date2 - $date1;
$playedtime = $interval / 60;
But still, it works like yours. I guess have to bring in the dates aswell?
但是，它仍然像您一样工作。我想还必须带上日期吗？
And again: My hard research and development helped me.
再说一遍：我的努力研究和开发帮助了我。
if (isset($_POST['calculate'])) {
$d1 = $_POST['started'];
$d2 = $_POST['ended'];
if ($d2 < $d1) {
$date22 = date('Y-m-');
$date222 = date('d')-1;
$date2 = $date22."".$date222;
} else {
$date2 = date('Y-m-d');
}
$date1 = date('Y-m-d');
$start_time = strtotime($date2.' '.$d1);
$end_time = strtotime($date1.' '.$d2); // or use date('Y-m-d H:i:s') for current time
$playedtime = round(abs($start_time - $end_time) / 60,2);
}
And that's how you calculate time over to the next day. //edit. First i had date1 jnd date2 switched. I need to -1 because this calculation only comes on next day and the first date vas yesterday.
这就是你如何计算到第二天的时间。//编辑。首先，我切换了 date1 jnd date2。我需要 -1 因为这个计算只出现在第二天和昨天的第一个日期。
After improving and a lot of brain power with my friend we came up to this:
在与我的朋友一起改进和大量脑力之后，我们想到了这个：
$begin=mktime(substr($_GET["start"], 0,2),substr($_GET["start"], 2,2),0,1,2,2003);
$end=mktime(substr($_GET["end"], 0,2),substr($_GET["end"], 2,2),0,1,3,2003);
$outcome=($end-$begin)-date("Z");
$minutes=date("i",$outcome)+date("H",$outcome)*60; //Echo minutes only
$hours = date("H:i", $outcome); //Echo time in hours + minutes like 01:10 or something.
So you actually need only 4 lines of code to get your result. You can take only minutes or show full time (like difference is 02:32) 2 hours and 32 minutes. What's most important: Still you can calculate overnight in 24 hour clock aka: Start time 11:50PM to let's say 01:00 AM (in 24 hour clock 23:50 - 01:00) because in 12 hour mode it works anyway.
所以你实际上只需要 4 行代码就可以得到你的结果。您可以只花几分钟或显示全时（例如差异是 02:32）2 小时 32 分钟。最重要的是：您仍然可以在 24 小时制中计算过夜，又名：开始时间 11:50PM 到上午 01:00（在 24 小时制中为 23:50 - 01:00），因为在 12 小时模式下它无论如何都可以工作。
What's most important: You don't have to format your input. You can use just plain 2300 as 23:00 input. This script will convert text field input to correct format by itself. Last script uses standard html form with method="get" but you can convert it to use POST method as well.
最重要的是：您不必格式化输入。您可以仅使用普通的 2300 作为 23:00 输入。此脚本将自行将文本字段输入转换为正确的格式。最后一个脚本使用带有 method="get" 的标准 html 表单，但您也可以将其转换为使用 POST 方法。
回答by xDemonsxXxSaintx
This is an updated version of one that was already submitted. It is with the seconds.
这是已经提交的版本的更新版本。它与秒。
function diff(start, end) {
start = start.split(":");
end = end.split(":");
var startDate = new Date(0, 0, 0, start[0], start[1], 0);
var endDate = new Date(0, 0, 0, end[0], end[1], 0);
var diff = endDate.getTime() - startDate.getTime();
var hours = Math.floor(diff / 1000 / 60 / 60);
diff -= hours * (1000 * 60 * 60);
var minutes = Math.floor(diff / 1000 / 60);
diff -= minutes * (1000 * 60);
var seconds = Math.floor(diff / 1000);
// If using time pickers with 24 hours format, add the below line get exact hours
if (hours < 0)
hours = hours + 24;
return (hours <= 9 ? "0" : "") + hours + ":" + (minutes <= 9 ? "0" : "") + minutes + (seconds<= 9 ? "0" : "") + seconds;
}
My Updated Version:
我的更新版本：
Allows for you to convert the dates into milliseconds and go off of that instead of splitting.
允许您将日期转换为毫秒，然后关闭而不是拆分。
Example Does -- Years/Months/Weeks/Days/Hours/Minutes/Seconds
示例是否 - 年/月/周/天/小时/分钟/秒
Example: https://jsfiddle.net/jff7ncyk/308/
回答by user8584085
With seconds you provided is not get result to me please find my updated function giving you the correct seconds here - By Dinesh J
您提供的秒数对我来说没有得到结果，请在此处找到我更新的函数，为您提供正确的秒数 - 作者 Dinesh J
function diff(start, end) {
start = start.split(":");
end = end.split(":");
var startDate = new Date(0, 0, 0, start[0], start[1],start[2], 0);
var endDate = new Date(0, 0, 0, end[0], end[1],end[2], 0);
var diff = endDate.getTime() - startDate.getTime();
var hours = Math.floor(diff / 1000 / 60 / 60);
diff -= hours * 1000 * 60 * 60;
var minutes = Math.floor(diff / 1000 / 60);
var seconds = Math.floor(diff / 1000)-120;
// If using time pickers with 24 hours format, add the below line get exact hours
if (hours < 0)
hours = hours + 24;
return (hours <= 9 ? "0" : "") + hours + ":" + (minutes <= 9 ? "0" : "") + minutes+ ":" + (seconds <= 9 ? "0" : "") + seconds;
}
回答by Abhishek Motiwale
Try This
尝试这个
var dif = ( new Date("1970-1-1 " + end-time) - new Date("1970-1-1 " + start-time) ) / 1000 / 60 / 60;
回答by mplungjan
Depending on what you allow to enter, this one will work. There may be some boundary issues if you want to allow 1am to 1pm
根据您允许输入的内容，这将起作用。如果你想允许凌晨 1 点到下午 1 点，可能会有一些边界问题
NOTE: This is NOT using a date objects or moment.js
注意：这不是使用日期对象或 moment.js
function pad(num) {
return ("0"+num).slice(-2);
}
function diffTime(start,end) {
var s = start.split(":"), sMin = +s[1] + s[0]*60,
e = end.split(":"), eMin = +e[1] + e[0]*60,
diff = eMin-sMin;
if (diff<0) { sMin-=12*60; diff = eMin-sMin }
var h = Math.floor(diff / 60),
m = diff % 60;
return "" + pad(h) + ":" + pad(m);
}
document.getElementById('button').onclick=function() {
document.getElementById('delay').value=diffTime(
document.getElementById('timeOfCall').value,
document.getElementById('timeOfResponse').value
);
}<input type="time" id="timeOfCall">
<input type="time" id="timeOfResponse">
<button type="button" id="button">CLICK</button>
<input type="time" id="delay">回答by Sanket Parchande
calTimeDifference(){
this.start = dailyattendance.InTime.split(":");
this.end = dailyattendance.OutTime.split(":");
var time1 = ((parseInt(this.start[0]) * 60) + parseInt(this.start[1]))
var time2 = ((parseInt(this.end[0]) * 60) + parseInt(this.end[1]));
var time3 = ((time2 - time1) / 60);
var timeHr = parseInt(""+time3);
var timeMin = ((time2 - time1) % 60);
}
回答by Shanshana Samarajeewa
TimeCount = function()
{
t++;
var ms = t;
if (ms == 99)
{
s++;
t = 0;
if ( s == 60)
{
m++;
s = 0;
}
}
Dis_ms = checkTime(ms);
Dis_s = checkTime(s);
Dis_m = checkTime(m);
document.getElementById("time_val").innerHTML = Dis_m + ":" + Dis_s+ ":" + Dis_ms;
}
function checkTime(i)
{
if (i<10) {
i = "0" + i;
}
return i;
} 回答by MetaSean
tl;dr
tl;博士
One off run
一关
const t1 = new Date(1579876543210) // your initial time
const t2 = new Date(1579987654321) // your later time
const diff = t2-t1
const SEC = 1000, MIN = 60 * SEC, HRS = 60 * MIN
const humanDiff = `${Math.floor(diff/HRS)}:${Math.floor((diff%HRS)/MIN).toLocaleString('en-US', {minimumIntegerDigits: 2})}:${Math.floor((diff%MIN)/SEC).toLocaleString('en-US', {minimumIntegerDigits: 2})}.${Math.floor(diff % SEC).toLocaleString('en-US', {minimumIntegerDigits: 4, useGrouping: false})}`
console.log("humanDiff:", humanDiff)
// > humanDiff: 30:51:51.0111As a function
作为函数
function humanDiff (t1, t2) {
const diff = Math.max(t1,t2) - Math.min(t1,t2)
const SEC = 1000, MIN = 60 * SEC, HRS = 60 * MIN
const hrs = Math.floor(diff/HRS)
const min = Math.floor((diff%HRS)/MIN).toLocaleString('en-US', {minimumIntegerDigits: 2})
const sec = Math.floor((diff%MIN)/SEC).toLocaleString('en-US', {minimumIntegerDigits: 2})
const ms = Math.floor(diff % SEC).toLocaleString('en-US', {minimumIntegerDigits: 4, useGrouping: false})
return `${hrs}:${min}:${sec}.${ms}`
}
const t1 = new Date(1579876543210)
const t2 = new Date(1579987654321)
console.log("humanDiff(t1, t2):", humanDiff(t1, t2))
// > humanDiff: 30:51:51.0111Explanation
解释
Adjust humanDifffor your maximum and minimum reportable increments and formatting needs:
调整humanDiff你的最大和最小报告增量和格式化的需求：
const t1 = new Date(1579876543210) // Set your initial time (`t1`)
const t2 = new Date(1579986654321) // , conclusion time (`t2`), and
const diff = t2-t1 // calculate their difference in milliseconds
console.log(" t2:", t2.toISOString()) // > t2: 2020-01-25T21:27:34.321Z
console.log(" t1:", t1.toISOString()) // > t1: 2020-01-24T14:35:43.210Z
console.log(" diff:", diff) // > diff: 111111111
// Set your constant time values for easy readability
const SEC = 1000
const MIN = 60 * SEC
const HRS = 60 * MIN
/* For a given unit
1) disregard any previously relevant units, e.g. to calculate minutes, we can
disregard all hours & focus on only the remainder - `(diff%HRS)`
2) divide the remainder by the given unit, e.g. for minutes, `(diff%HRS)/MIN`
3) disregard any remainder, e.g. again for minutes, `Math.floor((diff%HRS)/MIN)`
NOTE: for your maximum unit (HRS in the examples below) you probably _don't_
want to disregard high values, e.g. If the difference is >24 hrs and something,
you should either include a DAYS value, or simply display 30 hrs */
let hrs = Math.floor(diff/HRS)
let min = Math.floor((diff%HRS)/MIN)
let sec = Math.floor((diff%MIN)/SEC)
let ms = Math.floor(diff % SEC) // just the remainder
// BUT ms IS NOT ACTUALLY CORRECT, see humanDiff_3 for the fix ;-)
let humanDiff_1 = `${hrs}:${min}:${sec}.${ms}`
console.log("humanDiff_1:", humanDiff_1)
// > humanDiff_1: 30:51:51.111
sec = Math.round((diff%MIN)/SEC) // can also just round the last unit
const humanDiff_2 = `${hrs} hrs ${min} mins & ${sec} secs`
console.log("humanDiff_2:", humanDiff_2)
// > humanDiff_2: 30 hrs 51 mins & 51 secs
/* To ensure a set number of digits, format the numbers with `toLocaleString`'s
`minimumIntegerDigits`, if more than 3 digits, also use its `useGrouping` */
hrs = Math.floor(diff/HRS)
min = Math.floor((diff%HRS)/MIN).toLocaleString('en-US', {minimumIntegerDigits: 2})
sec = Math.floor((diff%MIN)/SEC).toLocaleString('en-US', {minimumIntegerDigits: 2})
ms = Math.floor(diff % SEC).toLocaleString('en-US', {minimumIntegerDigits: 4, useGrouping: false})
const humanDiff_3 = `${hrs}:${min}:${sec}.${ms}`
console.log("humanDiff_3:", humanDiff_3)
// > humanDiff_3: 30:51:51.0111
// NOTE: milliseconds are now 4 digits回答by user5371360
Try this: actually this a problem from codeeval.com
试试这个：实际上这是来自 codeeval.com 的问题
I solved it in this way .
我是这样解决的。
This program takes a file as the argument so i used a little node js to read the file.
该程序将文件作为参数，因此我使用了一个小节点 js 来读取文件。
Here is my code.
这是我的代码。
var fs = require("fs");
fs.readFileSync(process.argv[2]).toString().split('\n').forEach(function (line) {
if (line !== "") {
var arr = line.split(" ");
var arr1 = arr[0].split(":");
var arr2 = arr[1].split(":");
var time1 = parseInt(arr1[0])*3600 + parseInt(arr1[1])*60 + parseInt(arr1[2]);
var time2 = parseInt(arr2[0])*3600 + parseInt(arr2[1])*60 + parseInt(arr2[2]);
var dif = Math.max(time1,time2) - Math.min(time1,time2);
var ans = [];
ans[0] = Math.floor(dif/3600);
if(ans[0]<10){ans[0] = "0"+ans[0]}
dif = dif%3600;
ans[1] = Math.floor(dif/60);
if(ans[1]<10){ans[1] = "0"+ans[1]}
ans[2] = dif%60;
if(ans[2]<10){ans[2] = "0"+ans[2]}
console.log(ans.join(":"));
}
});
