MySQL 在 MariaDB 中,如何从表中选择前 10 行?
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/27133374/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
In MariaDB how do I select the top 10 rows from a table?
提问by Coffee
I just read online that MariaDB (which SQLZoo uses), is based on MySQL. So I thought that I can use ROW_NUMBER() function
我刚刚在网上读到 MariaDB(SQLZoo 使用的)是基于 MySQL 的。所以我想我可以使用 ROW_NUMBER() 函数
However, when I try this function in SQLZoo:
但是,当我在 SQLZoo 中尝试此功能时:
SELECT * FROM (
SELECT * FROM route
) TEST7
WHERE ROW_NUMBER() < 10
then I get this error :
然后我收到此错误:
Error: FUNCTION gisq.ROW_NUMBER does not exist
错误:FUNCTION gisq.ROW_NUMBER 不存在
回答by Mureinik
You can use the limit
clause:
您可以使用以下limit
条款:
SELECT * FROM route LIMIT 10
This can, of course, be used on a sorted query too:
当然,这也可以用于排序查询:
SELECT * FROM route ORDER BY some_field LIMIT 10
回答by declension
use LIMIT 10
at the end of your statement.
LIMIT 10
在语句的末尾使用。
See the MySQL SELECT documentation.
请参阅MySQL SELECT 文档。