php php随机x位数
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php random x digit number
提问by user1022585
I need to create a random number with x amount of digits.
我需要创建一个具有 x 位数的随机数。
So lets say x is 5, I need a number to be eg. 35562 If x is 3, then it would throw back something like; 463
所以让我们说 x 是 5，我需要一个数字，例如。35562 如果 x 是 3，那么它会抛出类似的东西；463
Could someone show me how this is done?
有人可以告诉我这是如何完成的吗？
回答by Marcus
You can use rand()together with pow()to make this happen:
$digits = 3;
echo rand(pow(10, $digits-1), pow(10, $digits)-1);
This will output a number between 100 and 999. This because 10^2 = 100 and 10^3 = 1000 and then you need to subtract it with one to get it in the desired range.
这将输出一个介于 100 和 999 之间的数字。这是因为 10^2 = 100 和 10^3 = 1000，然后您需要将其减去 1 以使其处于所需范围内。
If 005 also is a valid example you'd use the following code to pad it with leading zeros:
如果 005 也是一个有效示例，您可以使用以下代码用前导零填充它：
$digits = 3;
echo str_pad(rand(0, pow(10, $digits)-1), $digits, '0', STR_PAD_LEFT);
回答by Code Magician
I usually just use RAND()http://php.net/manual/en/function.rand.php
我通常只使用RAND()http://php.net/manual/en/function.rand.php
e.g.
例如
rand ( 10000 , 99999 );
for your 5 digit random number
为您的 5 位随机数
回答by Akshay Khale
Here is a simple solution without any loops or any hassle which will allow you to create random string with characters, numbers or even with special symbols.
这是一个没有任何循环或任何麻烦的简单解决方案，它允许您创建带有字符、数字甚至特殊符号的随机字符串。
$randomNum = substr(str_shuffle("0123456789"), 0, $x);
$randomNum = substr(str_shuffle("0123456789"), 0, $x);
where $xcan be number of digits
哪里$x可以是位数
Eg.
substr(str_shuffle("0123456789"), 0, 5);
例如。
substr(str_shuffle("0123456789"), 0, 5);
Results after a couple of executions
几次执行后的结果
98450
79324
23017
04317
26479
You can use the same code to generate random string also, like this
您也可以使用相同的代码来生成随机字符串，就像这样
$randomNum=substr(str_shuffle("0123456789abcdefghijklmnopqrstvwxyzABCDEFGHIJKLMNOPQRSTVWXYZ"), 0, $x);
Results with $x = 11
结果与 $x = 11
FgHmqpTR3Ox
O9BsNgcPJDb
1v8Aw5b6H7f
haH40dmAxZf
0EpvHL5lTKr
回答by halfdan
You can use rand($min, $max)for that exact purpose.
您可以将其rand($min, $max)用于该确切目的。
In order to limit the values to values with x digits you can use the following:
为了将值限制为 x 位的值，您可以使用以下命令：
$x = 3; // Amount of digits
$min = pow(10,$x);
$max = pow(10,$x+1)-1);
$value = rand($min, $max);
回答by Blender
Treat your number as a list of digits and just append a random digit each time:
将您的号码视为数字列表，每次只附加一个随机数字：
function n_digit_random($digits) {
$temp = "";
for ($i = 0; $i < $digits; $i++) {
$temp .= rand(0, 9);
}
return (int)$temp;
}
Or a purely numerical solution:
或者纯粹的数值解：
function n_digit_random($digits)
return rand(pow(10, $digits - 1) - 1, pow(10, $digits) - 1);
}
回答by animuson
回答by Alex
rand(1000, 9999);works more faster than x4 times rand(0,9);
rand(1000, 9999);工作速度比 x4 倍快 rand(0,9);
benchmark:
基准：
rand(1000, 9999) : 0.147 sec.
rand(0,9)x4 times : 0.547 sec.
both functions was running in 100000 iterations to make results more explicit
两个函数都在 100000 次迭代中运行，以使结果更加明确
回答by AMB
the simplest way i can think of is using randfunction with str_pad
我能想到的最简单的方法是使用rand函数str_pad
<?php
echo str_pad(rand(0,999), 5, "0", STR_PAD_LEFT);
?>
In above example , it will generate random number in range 0 to 999.
在上面的例子中，它将生成0 到 999范围内的随机数。
And having 5digits.
并且有5位数。
回答by philip mudenyo
function random_number($size = 5)
{
$random_number='';
$count=0;
while ($count < $size )
{
$random_digit = mt_rand(0, 9);
$random_number .= $random_digit;
$count++;
}
return $random_number;
}
回答by Rene Pot
do it with a loop:
用循环来做：
function randomWithLength($length){
$number = '';
for ($i = 0; $i < $length; $i++){
$number .= rand(0,9);
}
return (int)$number;
}
