PHP/REGEX：获取括号内的字符串
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PHP/REGEX: Get a string within parentheses
提问by Macks
This is a really simple problem, but I couldn't find a solution anywhere.
这是一个非常简单的问题，但我在任何地方都找不到解决方案。
I'm try to use preg_match or preg_match_all to obtain a string from within parentheses, but without the parentheses.
我尝试使用 preg_match 或 preg_match_all 从括号内获取字符串，但没有括号。
So far, my expression looks like this:
到目前为止，我的表情是这样的：
\([A-Za-z0-9 ]+\)
and returns the following result:
并返回以下结果：
3(hollow highlight) 928-129 (<- original string)
(hollow highlight) (<- result)
3（空心高亮）928-129（<-原始字符串）
（空心突出显示）（<- 结果）
What i want is the string within parentheses, but without the parentheses. It would look like this:
我想要的是括号内的字符串，但没有括号。它看起来像这样：
hollow highlight
空心亮点
I could probably replace the parentheses afterwards with str_replace or something, but that doesn't seem to be a very elegant solution to me.
之后我可能可以用 str_replace 或其他东西替换括号，但这对我来说似乎不是一个非常优雅的解决方案。
What do I have to add, so the parentheses aren't included in the result?
我必须添加什么，以便括号不包含在结果中？
Thanks for your help, you guys are great! :)
谢谢你的帮助，你们很棒！:)
回答by Piotr Olaszewski
try:
尝试：
preg_match('/\((.*?)\)/', $s, $a);
output:
输出：
Array
(
[0] => (hollow highlight)
[1] => hollow highlight
)
回答by Andrew Cheong
You just need to add capturing parenthesis, in addition to your escaped parenthesis.
除了转义括号之外，您只需要添加捕获括号。
<?php
$in = "hello (world), my name (is andrew) and my number is (845) 235-0184";
preg_match_all('/\(([A-Za-z0-9 ]+?)\)/', $in, $out);
print_r($out[1]);
?>
This outputs:
这输出：
Array ( [0] => world [1] => is andrew [2] => 845 )
