Javascript 表单提交后隐藏/显示 Div？
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Hide/Show Div after form submit?
提问by Jessica
Hi I'm having some trouble getting this to work, pretty simple all I am wanting to do is show a div once my html form is submitted.
嗨，我在让它工作时遇到了一些麻烦，很简单，我想要做的就是在提交我的 html 表单后显示一个 div。
<head>
<script type="text/javascript">
function showHide() {
var div = document.getElementById(hidden_div);
if (div.style.display == 'none') {
div.style.display = '';
}
else {
div.style.display = 'none';
}
}
</script>
</head>
<body>
<form method="post" name="installer">
<label>Home Keyword</label>
<br />
<input type="text" name="hello" value="">
<br />
<input type="submit" value="" name="submit" onsubmit="showHide()">
</form>
<div id="hidden_div" style="display:none">
<p>Show me when form is submitted :) </p>
</div>
</body>
Any help would be much appreciated thank you :)
任何帮助将不胜感激谢谢:)
回答by C???
I think you're just missing quotes around "hidden_div" in your document.getElementById("hidden_div")call!
我认为您只是在document.getElementById("hidden_div")通话中缺少“hidden_div”周围的引号！
But actually, your page is probably posting back, resetting the state of the page and thus leaving hidden_div seemingly always in a hidden state -- are you intending on handling the form submission via AJAX?
但实际上，您的页面可能正在回发，重置页面状态，从而使 hidden_div 似乎始终处于隐藏状态——您是否打算通过 AJAX 处理表单提交？
If you want to see the intended behavior, you should move the showHide()call to the <form>element, and return false after it:
如果你想看到预期的行为，你应该移动showHide()对<form>元素的调用，并在它之后返回 false：
<form method="post" name="installer" onsubmit="showHide(); return false;">
and leave the submit button as:
并将提交按钮保留为：
<input type="submit" value="" name="submit" />
Also note that you haven't self-closed the <input />button tag, or given any text to show inside it.
另请注意，您没有自行关闭<input />按钮标签，也没有在其中显示任何文本。
回答by Adeel
you need to put showhidefunction on form onsubmitinstead of input
你需要把showhide函数放在表单上onsubmit而不是input
<form method="post" name="installer" onsubmit="showHide()">
you are also missing quotes as @Cory mentioned
你也缺少@Cory提到的引号
