Bash one liner - 测试一个文件是否存在，如果它执行其他错误退出并提供源
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时间：2020-09-18 10:51:21 来源:igfitidea点击:
Bash one liner - Test if a file exists and source if it does other exit with error
提问by skanga
In other words I want to make this into a one-liner:
换句话说，我想把它变成一个单行：
test -e ${MY_HOME}/setup-env.sh || { echo "ERROR: MY_HOME not defined or does not contain srtup-env.sh" 1>&2 ; exit 1; }
. ${MY_HOME}/setup-env.sh
回答by anubhava
You can use this one liner:
您可以使用这种衬垫：
[[ -e "${MY_HOME}/setup-env.sh" ]] && source "${MY_HOME}/setup-env.sh" || { echo "ERROR: MY_HOME not defined or does not contain srtup-env.sh" 1>&2 ; exit 1; }
回答by konsolebox
[[ -e ${MY_HOME}/setup-env.sh ]] && { source "${MY_HOME}/setup-env.sh"; exit; }; echo "ERROR: MY_HOME not defined or does not contain setup-env.sh" >&2; exit 1
Or if non-bash:
或者如果非 bash：
test -e "${MY_HOME}/setup-env.sh" && { . "${MY_HOME}/setup-env.sh"; exit; }; echo "ERROR: MY_HOME not defined or does not contain setup-env.sh" >&2; exit 1
It's actually not a "one-liner" for me but just a condensed form.
对我来说，它实际上不是“单行”，而只是一种浓缩形式。
