使用 PHP 从字符串中提取 URL
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Extract URL's from a string using PHP
提问by Azraar Azward
How can we use PHP to identify URL's in a string and store them in an array?
我们如何使用 PHP 来识别字符串中的 URL 并将它们存储在数组中？
Cannot use the explodefunction if the URL contains a comma, it wont give correct results.
explode如果 URL 包含逗号，则无法使用该功能，它不会给出正确的结果。
回答by aampudia
REGEX is the answer for your problem. Taking the Answer of Object Manipulator.. all it's missing is to exclude "commas", so you can try this code that excludes them and gives 3 separated URL's as output:
REGEX 是您问题的答案。接受 Object Manipulator 的答案 .. 它所缺少的只是排除“逗号”，因此您可以尝试使用此代码排除它们并给出 3 个分隔的 URL 作为输出：
$string = "The text you want to filter goes here. http://google.com, https://www.youtube.com/watch?v=K_m7NEDMrV0,https://instagram.com/hellow/";
preg_match_all('#\bhttps?://[^,\s()<>]+(?:\([\w\d]+\)|([^,[:punct:]\s]|/))#', $string, $match);
echo "<pre>";
print_r($match[0]);
echo "</pre>";
and the output is
输出是
Array
(
[0] => http://google.com
[1] => https://www.youtube.com/watch?v=K_m7NEDMrV0
[2] => https://instagram.com/hellow/
)
回答by JiteshNK
please try to use below regex
请尝试使用下面的正则表达式
$regex = '/https?\:\/\/[^\",]+/i';
preg_match_all($regex, $string, $matches);
echo "<pre>";
print_r($matches[0]);
Hope this will work for you
希望这对你有用
回答by Object Manipulator
You can try Regex here:
你可以在这里尝试正则表达式：
$string = "The text you want to filter goes here. http://google.com, https://www.youtube.com/watch?v=K_m7NEDMrV0,https://instagram.com/hellow/";
preg_match_all('#\bhttps?://[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|/))#', $string, $match);
echo "<pre>";
print_r($match[0]);
echo "</pre>";
This gives the following output:
这给出了以下输出：
Array
(
[0] => http://google.com
[1] => https://www.youtube.com/watch?v=K_m7NEDMrV0,https://instagram.com/hellow/
)
回答by Prassd Nidode
$urlstring = "The text you want to filter goes here. http://google.com, https://www.youtube.com/watch?v=K_m7NEDMrV0,https://instagram.com/hellow/";
preg_match_all('#\bhttps?://[^,\s()<>]+(?:\([\w\d]+\)|([^,[:punct:]\s]|/))#', $urlstring , $result);
print_r($result[0]);
回答by khan
try this
尝试这个
function getUrls($string)
{
$regex = '/https?\:\/\/[^\" ]+/i';
preg_match_all($regex, $string, $matches);
return ($matches[0]);
}
$urls = getUrls($string);
print_r($urls);
or
或者
$str = '<a href="http://foobar.com"> | Hello world Im a http://google.fr | Did you mean:http://google.fr/index.php?id=1&b=6#2310';
$pattern = '`.*?((http|ftp)://[\w#$&+,\/:;[email protected]]+)[^\w#$&+,\/:;[email protected]]*?`i';
if (preg_match_all($pattern,$str,$matches))
{
print_r($matches[1]);
}
it will works
它会起作用
回答by Prassd Nidode
$string = "The text you want to filter goes here. http://google.com,
https://www.youtube.com/watch?v=K_m7NEDMrV0,https://instagram.com/hellow/";
preg_match_all('#\bhttps?://[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|/))#',
$string, $match);
echo "<pre>"; $arr = explode(",", $match[0][1]);
print_r($match[0][0]); print_r($arr); echo "</pre>";
