php 从包含文件返回
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Return from include file
提问by bear
in PHP, how would one return from an included script back to the script where it had been included from?
在 PHP 中，如何从包含的脚本返回到包含它的脚本？
IE:
IE：
1 - main script 2 - application 3 - included
1 - 主脚本 2 - 应用程序 3 - 包括
Basically, I want to get back from 3 to 2, return() doesn't work.
基本上，我想从 3 回到 2， return() 不起作用。
Code in 2 - application
代码 2 - 应用程序
$page = "User Manager";
if($permission["13"] !=='1'){
include("/home/radonsys/public_html/global/error/permerror.php");
return();
}
回答by Frank Farmer
includeme.php:
包含.php：
$x = 5;
return $x;
main.php:
主文件：
$myX = require 'includeme.php';
also gives the same result
也给出了相同的结果
This is one of those little-known features of PHP, but it can be kind of nice for setting up really simple config files.
这是 PHP 鲜为人知的特性之一，但它可以很好地设置非常简单的配置文件。
回答by instanceof me
returnshould work, as stated in the documentation.
If the current script file was include()ed or require()ed, then control is passed back to the calling file. Furthermore, if the current script file was include()ed, then the value given to return() will be returned as the value of the include() call.
如果当前脚本文件被include()ed 或require()ed，则控制被传递回调用文件。此外，如果当前脚本文件被 include() 处理，则给 return() 的值将作为 include() 调用的值返回。
回答by Gravy
I know that this has already been answered, but I think I have a nice solution...
我知道这已经得到了回答，但我想我有一个很好的解决方案......
main.php
主文件
function test()
{
$data = 'test';
ob_start();
include( dirname ( __FILE__ ) . '/included.php' );
return ob_get_clean();
}
included.php
包含.php
<h1>Test Content</h1>
<p>This is the data: <?php echo $data; ?></p>
I just included $datato show that you can still pass data to the included file, as well as return the included file.
我只是$data为了表明您仍然可以将数据传递给包含的文件，以及返回包含的文件。
回答by Eevee
Hm, the PHP manualdisagrees with you. returnshould bail you out of an included file. It won't work from within a function, of course.
嗯，PHP 手册不同意你的看法。 return应该让你摆脱包含的文件。当然，它不会在函数内工作。
