Javascript Javascript将空格或引号上的字符串拆分为数组
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Javascript split string on space or on quotes to array
提问by Remi
var str = 'single words "fixed string of words"';
var astr = str.split(" "); // need fix
I would like the array to be like this:
我希望数组是这样的：
var astr = ["single", "words", "fixed string of words"];
回答by YOU
str.match(/\w+|"[^"]+"/g)
//single, words, "fixed string of words"
回答by dallin
The accepted answer is not entirely correct. It separates on non-space characters like . and - and leaves the quotes in the results. The better way to do this so that it excludes the quotes is with capturing groups, like such:
接受的答案并不完全正确。它分隔非空格字符，如 . 和 - 并在结果中留下引号。执行此操作以排除引号的更好方法是使用捕获组，例如：
//The parenthesis in the regex creates a captured group within the quotes
var myRegexp = /[^\s"]+|"([^"]*)"/gi;
var myString = 'single words "fixed string of words"';
var myArray = [];
do {
//Each call to exec returns the next regex match as an array
var match = myRegexp.exec(myString);
if (match != null)
{
//Index 1 in the array is the captured group if it exists
//Index 0 is the matched text, which we use if no captured group exists
myArray.push(match[1] ? match[1] : match[0]);
}
} while (match != null);
myArray will now contain exactly what the OP asked for:
myArray 现在将包含 OP 要求的内容：
single,words,fixed string of words
回答by Sean Kinsey
This uses a mix of split and regex matching.
这使用了拆分和正则表达式匹配的混合。
var str = 'single words "fixed string of words"';
var matches = /".+?"/.exec(str);
str = str.replace(/".+?"/, "").replace(/^\s+|\s+$/g, "");
var astr = str.split(" ");
if (matches) {
for (var i = 0; i < matches.length; i++) {
astr.push(matches[i].replace(/"/g, ""));
}
}
This returns the expected result, although a single regexp should be able to do it all.
这将返回预期的结果，尽管单个正则表达式应该能够完成所有操作。
// ["single", "words", "fixed string of words"]
UpdateAnd this is the improved version of the the method proposed by S.Mark
更新这是S.Mark提出的方法的改进版本
var str = 'single words "fixed string of words"';
var aStr = str.match(/\w+|"[^"]+"/g), i = aStr.length;
while(i--){
aStr[i] = aStr[i].replace(/"/g,"");
}
// ["single", "words", "fixed string of words"]
回答by Qian Chen
Here might be a complete solution: https://github.com/elgs/splitargs
这里可能是一个完整的解决方案：https: //github.com/elgs/splitargs
回答by Tsuneo Yoshioka
ES6 solution supporting:
ES6 解决方案支持：
- Split by space except for inside quotes
- Removing quotes but not for backslash escaped quotes
- Escaped quote become quote
- Can put quotes anywhere
- 除内引号外，按空格分割
- 删除引号但不用于反斜杠转义引号
- 转义报价成为报价
- 可以在任何地方放置引号
Code:
代码：
str.match(/\?.|^$/g).reduce((p, c) => {
if(c === '"'){
p.quote ^= 1;
}else if(!p.quote && c === ' '){
p.a.push('');
}else{
p.a[p.a.length-1] += c.replace(/\(.)/,"");
}
return p;
}, {a: ['']}).a
Output:
输出：
[ 'single', 'words', 'fixed string of words' ]
回答by tim.breeding
This will split it into an array and strip off the surrounding quotes from any remaining string.
这会将其拆分为一个数组，并从任何剩余的字符串中去除周围的引号。
const parseWords = (words = '') =>
(words.match(/[^\s"]+|"([^"]*)"/gi) || []).map((word) =>
word.replace(/^"(.+(?="$))"$/, ''))回答by julianYaman
This soulution would work for both double (") and single (') quotes:
此解决方案适用于双 (") 和单 (') 引号：
Code:
代码：
str.match(/[^\s"']+|"([^"]*)"/gmi)
// ["single", "words", "fixed string of words"]
Here it shows how this regular expression would work: https://regex101.com/r/qa3KxQ/2
这里展示了这个正则表达式的工作原理：https: //regex101.com/r/qa3KxQ/2
回答by user655489
I noticed the disappearing characters, too. I think you can include them - for example, to have it include "+" with the word, use something like "[\w\+]" instead of just "\w".
我也注意到消失的角色。我认为您可以包含它们 - 例如，要在单词中包含“+”，请使用“[\w\+]”之类的内容，而不仅仅是“\w”。
