Java @JsonProperty 未按预期工作
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@JsonProperty not working as expected
提问by Ayodeji
I get the following exception when i consume a restful webservice using Spring RestTemplate
当我使用 Spring RestTemplate 使用一个安静的网络服务时，我得到以下异常
com.fasterxml.Hymanson.databind.exc.UnrecognizedPropertyException: Unrecognized field "IMP-SourceTxnId" (class com.model.ResponseBaseParameters) not marked as ignorable (4 known properties: , "sourceTxnId", "incommTxnId", "responseCode", "responseText"])
at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@2f2ddd7c; line: 1, column: 130] (through reference chain: com.incomm.ife.model.rogers.RogersTransactionResponse["responseBaseParameters"]->com.incomm.ife.model.rogers.ResponseBaseParameters["IMP-SourceTxnId"])
at com.fasterxml.Hymanson.databind.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:79)
at com.fasterxml.Hymanson.databind.DeserializationContext.reportUnknownProperty(DeserializationContext.java:555)
at com.fasterxml.Hymanson.databind.deser.std.StdDeserializer.handleUnknownProperty(StdDeserializer.java:708)
at com.fasterxml.Hymanson.databind.deser.BeanDeserializerBase.handleUnknownProperty(BeanDeserializerBase.java:1159)
at com.fasterxml.Hymanson.databind.deser.BeanDeserializer.deserializeFromObject(BeanDeserializer.java:315)
at com.fasterxml.Hymanson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:121)
at com.fasterxml.Hymanson.databind.deser.SettableBeanProperty.deserialize(SettableBeanProperty.java:449)
at com.fasterxml.Hymanson.databind.deser.impl.MethodProperty.deserializeAndSet(MethodProperty.java:98)
at com.fasterxml.Hymanson.databind.deser.BeanDeserializer.deserializeFromObject(BeanDeserializer.java:295)
at com.fasterxml.Hymanson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:121)
at com.fasterxml.Hymanson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:2888)
at com.fasterxml.Hymanson.databind.ObjectMapper.readValue(ObjectMapper.java:2094)
at org.springframework.http.converter.json.MappingHymanson2HttpMessageConverter.readInternal(MappingHymanson2HttpMessageConverter.java:123)
... 54 more
The response parameter is
响应参数是
{
"responseBaseParameters":
{
"responseCode": "32",
"responseText": "Invalid Request",
"incommTxnId": null,
"IMP-SourceTxnId": "551932ba-6af4-44f9-ab98-db5bc96e962b"
}
}
and my POJO class is
我的 POJO 课程是
public class ResponseBaseParameters {
private String responseCode;
private String responseText;
private String incommTxnId;
@JsonProperty("IMP-SourceTxnId")
private String sourceTxnId;
public String getResponseCode() {
return responseCode;
}
public void setResponseCode(String responseCode) {
this.responseCode = responseCode;
}
public String getResponseText() {
return responseText;
}
public void setResponseText(String responseText) {
this.responseText = responseText;
}
public String getIncommTxnId() {
return incommTxnId;
}
public void setIncommTxnId(String incommTxnId) {
this.incommTxnId = incommTxnId;
}
public String getSourceTxnId() {
return sourceTxnId;
}
public void setSourceTxnId(String sourceTxnId) {
this.sourceTxnId = sourceTxnId;
}
}
Please any insight as to why i am getting this error. Thanks
请了解为什么我会收到此错误。谢谢
回答by Josiel Novaes
There are many implementations of "REST API" and they conflict with each other. After a lot of time, I resolved it with this configuration:
“REST API”有很多实现，它们相互冲突。很多时间后，我用这个配置解决了它：
import com.fasterxml.Hymanson.annotation.JsonProperty;
...
@JsonProperty("cep")
private String cep;
Must have that JsonProperty with this package not org.codehaus...
必须有这个包的 JsonProperty 而不是 org.codehaus ......
<dependency>
<groupId>com.sun.jersey</groupId>
<artifactId>jersey-client</artifactId>
<version>1.19</version>
<scope>test</scope>
</dependency>
In summary: jersey client 1, Hymanson json property and remove all others jaxrc libs.
总结：jersey client 1, Hymanson json property 并删除所有其他 jaxrc libs。
Obs:. I used Hymanson because the container already provided, but, if it works for you, you could test another combinations.
奥布斯：。我使用 Hymanson 是因为容器已经提供，但是，如果它适合您，您可以测试其他组合。
