php 如何从 URL 获取图像文件的大小？
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How can I the size of an image file from the URL?
提问by James
Images and script are hosted on the same account (one site), but we know only the URL of the image.
图像和脚本托管在同一个帐户（一个站点）上，但我们只知道图像的 URL。
$image = "http://example.com/images/full-1091.jpg"
How can we get the sizeof this file?
我们如何获得这个文件的大小？
Pseudo-code:
伪代码：
{ do something with $image and get $image_size }
echo $image_size;
I would prefer $image_sizeto be formatted in human-readable file sizes, like "156,8 Kbytes" or "20,1 Mbytes".
我更喜欢$image_size以人类可读的文件大小进行格式化，例如“156,8 KB”或“20,1 Mbytes”。
回答by Sarfraz
Use filesizefunction like this:
使用这样的filesize功能：
echo filesize($filename) . ' bytes';
You can also format the unit of the size with this function:
您还可以使用此功能格式化大小的单位：
function format_size($size) {
$sizes = array(" Bytes", " KB", " MB", " GB", " TB", " PB", " EB", " ZB", " YB");
if ($size == 0) { return('n/a'); } else {
return (round($size/pow(1024, ($i = floor(log($size, 1024)))), 2) . $sizes[$i]); }
}
回答by Pekka
Images and script hosted on the same account (one site).
托管在同一帐户（一个站点）上的图像和脚本。
Then don't use a URL: Use the direct file path and filesize().
然后不要使用 URL：使用直接文件路径和filesize().
回答by Mahdi Jazini
Please Note:
请注意：
The result of filesize()function are cached! Use clearstatcache()to clear the cache...
filesize()函数的结果被缓存了！使用clearstatcache()清除缓存...
source: http://www.w3schools.com/php/func_filesystem_filesize.asp
来源：http: //www.w3schools.com/php/func_filesystem_filesize.asp
回答by Your Common Sense
echo filesize($_SERVER['DOCUMENT_ROOT']."/images/full-1091.jpg");
note that http://site.com/images/full-1091.jpgis nota file
请注意，这http://site.com/images/full-1091.jpg不是文件
as for the formatted output ("156,8 Kbytes" or "20,1 Mbytes") try to help yourself and use search. There is a ton of answers to this question already.
至于格式化的输出（“156,8 Kbytes”或“20,1 Mbytes”）尝试帮助自己并使用搜索。这个问题已经有很多答案了。
回答by Ankur Mukherjee
<?php
$contents=file_get_contents("http://site.com/images/full-1091.jpg");
// var_dump($contents);
// $fp =fopen("1.jpeg","w");
file_put_contents("1.jpeg",$contents);
$size= filesize("1.jpeg");
echo $size."in Bytes";
?>
Check this it can work for you
检查这个它可以为你工作
