如何用 HTML 和 PHP 代码注释掉多行？
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How do I comment out multiple lines with HTML and PHP code in it?
提问by fuddin
I want to comment out the whole code below. What would be the easiest way to do it without using multiple comments? Thanks in advance.
我想注释掉下面的整个代码。在不使用多个评论的情况下，最简单的方法是什么？提前致谢。
<nav id="site-navigation" class="main-navigation" role="navigation">
<h3 class="menu-toggle"><?php _e( 'Menu', 'twentytwelve' ); ?></h3>
<a class="assistive-text" href="#content" title="<?php esc_attr_e( 'Skip to content', 'twentytwelve' ); ?>"><?php _e( 'Skip to content', 'twentytwelve' ); ?></a>
<?php wp_nav_menu( array( 'theme_location' => 'primary', 'menu_class' => 'nav-menu' ) ); ?>
</nav><!-- #site-navigation -->
回答by Fisch
just surround the entire block with php comments like this:
只需用这样的 php 注释包围整个块：
<?php /*
<nav id="site-navigation" class="main-navigation" role="navigation">
<h3 class="menu-toggle"><?php _e( 'Menu', 'twentytwelve' ); ?></h3>
<a class="assistive-text" href="#content" title="<?php esc_attr_e( 'Skip to content', 'twentytwelve' ); ?>"><?php _e( 'Skip to content', 'twentytwelve' ); ?></a>
<?php wp_nav_menu( array( 'theme_location' => 'primary', 'menu_class' => 'nav-menu' ) ); ?>
</nav><!-- #site-navigation -->
*/?>
回答by Flaxbeard
<!-- <nav id="site-navigation" class="main-navigation" role="navigation">
<h3 class="menu-toggle"><?php _e( 'Menu', 'twentytwelve' ); ?></h3>
<a class="assistive-text" href="#content" title="<?php esc_attr_e( 'Skip to content', 'twentytwelve' ); ?>"><?php _e( 'Skip to content', 'twentytwelve' ); ?></a>
<?php wp_nav_menu( array( 'theme_location' => 'primary', 'menu_class' => 'nav-menu' ) ); ?>
</nav> -->
Should suffice. They are multiline comments.
应该够了。它们是多行注释。
This should help: https://stackoverflow.com/questions/5781375/comment-out-html-and-php-together
这应该会有所帮助：https: //stackoverflow.com/questions/5781375/comment-out-html-and-php-together
