php Foreach 循环遍历多维数组
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Foreach loop through multidimensional array
提问by intelis
I have this set of data that I get from htmlform. It is basically a multidimensional array.
我有这组从html表单中获得的数据。它基本上是一个多维数组。
Data
数据
array(3) {
["r1"]=>
array(2) {
[0]=>
string(1) "2"
[1]=>
string(1) "4"
}
["r2"]=>
array(2) {
[0]=>
string(1) "5"
[1]=>
string(2) "96"
}
["tekma_id"]=>
array(2) {
[0]=>
string(1) "7"
[1]=>
string(1) "8"
}
}
Problem:What i want to do, is to go over this array and for each iteration create a data variable(array).
问题：我想要做的是遍历这个数组并为每次迭代创建一个数据变量（array）。
So for example:
例如：
First iteration:
第一次迭代：
$data = array(
'r1' => '2'
'r2' => '5'
'tekma_id' => '7'
)
Second iteration:
第二次迭代：
$data = array(
'r1' => '4'
'r2' => '96'
'tekma_id' => '8'
)
I've tried with this:
我试过这个：
foreach ($data as $key => $value) {
foreach ($value as $index => $v) {
echo "<br>";
echo "r1: $v";
echo "<br>";
echo "r2: $v";
echo "<br>";
echo "tekma_id: $v";
}
}
But it didn't work. Sorry for my bad english and thanks for any help. Cheers!
但它没有用。抱歉我的英语不好，感谢您的帮助。干杯!
回答by George Brighton
How about this?
这个怎么样？
$array = array(
'r1' => array(2, 4),
'r2' => array(5, 96),
'tekma_id' => array(7, 8));
$keys = array_keys($data);
$iterations = count($array[$keys[0]]);
for($i = 0; $i < $iterations; $i++) {
$data = array();
foreach($array as $key => $value) {
$data[$key] = $value[$i];
}
print_r($data);
}
Output:
输出：
Array
(
[r1] => 2
[r2] => 5
[tekma_id] => 7
)
Array
(
[r1] => 4
[r2] => 96
[tekma_id] => 8
)
回答by Aleksandr Khristenko
Try this:
尝试这个：
$keys = array_keys($data);
$count = count(array_shift(array_values($data)));
for ($i = 0; $i<$count; $i++) {
$result = array();
foreach ($keys as $key) {
$result[$key] = $data[$key][$i];
}
var_dump($result);
}
