javascript 以“09:00 AM”格式对包含时间的字符串数组进行排序？
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Sort string array containing time in format '09:00 AM'?
提问by user2458935
I am trying to sort my array.
我正在尝试对我的数组进行排序。
The array consists of data in time format.
该数组由时间格式的数据组成。
Array:
大批：
'9:15 AM', '10:20 AM', '02:15 PM'
How should I sort it ?
我应该如何排序？
I'm getting this data usig json service & using it to list events in jquery mobile's listview . but I want to sort events by time .
我正在使用 json 服务获取此数据并使用它在 jquery mobile 的 listview 中列出事件。但我想按时间对事件进行排序。
UPDATE: HOW I SORTED DATA FROM JSON BY BOTH DATE AND TIME:
更新：我如何按日期和时间从 JSON 中排序数据：
For my particular problem of sorting data got using json by date & time I done like this :
对于我按日期和时间使用 json 对数据进行排序的特殊问题，我是这样做的：
$.getJSON(serviceURL + 'read.php?month_no='+month_no, function(data) {
events = data.data;
events.sort(function(a,b){
a = new Date(a.event_date+' '+a.event_time);
b = new Date(b.event_date+' '+b.event_time);
return a<b?-1:a>b?1:0;
});
});
回答by Shobhit Sharma
Try this
试试这个
var times = ['01:00 am', '06:00 pm', '12:00 pm', '03:00 am', '12:00 am'];
times.sort(function (a, b) {
return new Date('1970/01/01 ' + a) - new Date('1970/01/01 ' + b);
});
console.log(times);
回答by Dustin Silk
My solution (For times formated like "11:00", "16:30"..)
我的解决方案（对于格式为“11:00”、“16:30”..的时间）
sortTimes: function (array) {
return array.sort(function (a, b) {
if (parseInt(a.split(":")[0]) - parseInt(b.split(":")[0]) === 0) {
return parseInt(a.split(":")[1]) - parseInt(b.split(":")[1]);
} else {
return parseInt(a.split(":")[0]) - parseInt(b.split(":")[0]);
}
})
}
In case someone wanted to know haha
万一有人想知道哈哈
回答by NINCOMPOOP
Implement the sort(compare)function and compare the date string using any arbitrary date :
实现sort(compare)函数并使用任意日期比较日期字符串：
Array.sort(function (a, b) {
return Date.parse('01/01/2013 '+a) - Date.parse('01/01/2013 '+b)
});
01/01/2013is any arbitrary date.
01/01/2013是任意日期。
回答by rafaelcastrocouto
var a = ['9:15 AM', '10:20 AM', '02:15 PM'];
var sort = function(a){
var sa = [],
d = new Date(),
ds = d.toDateString();
for(var i = 0; i < a.length; i++){
d = new Date(ds + ' ' + a[i]);
sa.push(d);
}
sa.sort(function(a, b){return a.getTime() - b.getTime();})
return sa;
}
回答by scottmgerstl
function sortTimes(arrayOfTimes) {
return arrayOfTimes.sort((a, b) => {
const aParts = getNumericParts(a);
const bParts = getNumericParts(b);
// Sorts by hour then minute
return aParts[0] - bParts[0] || aParts[1] - bParts[1];
});
function getNumericParts(time) {
// accounts formats of 9:15 AM and 09:15:30 but does not handle AM/PM in comparison
return time.split(' ')[0].split(':').map(x => +x);
}
}
Here's a more concise and performant variation of Dustin Silk's answer. It takes into account formats of 9:15 AM, 09:15, and 09:15:30 though it does not sort based on seconds. You could add that by using || aParts[2] - bParts[2]as a part of the return statement.
这是 Dustin Silk 答案的更简洁、更高效的变体。它考虑了 9:15 AM、09:15 和 09:15:30 的格式，但它不基于秒进行排序。您可以通过将其|| aParts[2] - bParts[2]用作 return 语句的一部分来添加它。
sortTimes(['08:00', '09:00', '05:00', '08:15', '08:00'])
// Output ["05:00", "08:00", "08:00", "08:15", "09:00"]
