在 linux 上查看文件大小
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watch file size on linux
提问by texai
I want to watch the growing size of a single file, so i use this command:
我想观察单个文件不断增长的大小，因此我使用以下命令：
texai@maelstrom ~$ ls -lh club_prod.sql | awk '{print }'
116M
Now I want to watch that result each 5 seconds so:
现在我想每 5 秒看一次结果，所以：
texai@maelstrom ~$ watch -n 5 ls -lh club_prod.sql | awk '{print }'
but this command doesn't return any result
但此命令不返回任何结果
采纳答案by larsks
You're piping the output of watchinto awk. If you simplify your command line, what you have is:
您正在将 的输出通过管道传输watch到awk. 如果你简化你的命令行，你所拥有的是：
watch <some arguments> | awk '{print }'
That's not what you want. Try:
那不是你想要的。尝试：
watch -n 5 "ls -lh club_prod.sql | awk '{print $5}'"
回答by myki
watch -n 5 "ls -lh club_prod.sql | awk '{print $5}'"
回答by geekosaur
You need to quote the pipeline so that it is done withinwatch.
您需要引用管道，以便在watch.
watch -n 5 "ls -lh club_prod.sql | awk '{print $5}'"
Note also the \added to \$5because the outer quotes are now double quotes, in which $-variables are expanded. (Other methods of quoting are generally uglier than this.)
还要注意\添加到\$5因为外部引号现在是双引号，其中$-variables 被扩展。（其他引用方法通常比这更丑。）
回答by tamasgal
watch -n 5 "du -h club_prod.sql"
回答by JacaHyman
Not exactly related, but if you want to monitor growth rate of some file, you could use following command:
不完全相关，但如果您想监控某个文件的增长率，您可以使用以下命令：
tail -f yourfile.txt | pv > /dev/null
tail -f yourfile.txt | pv > /dev/null
tail -f- outputs data appended to filepv- measures data flow through pipe> /dev/null- standard output gets discarded
tail -f- 输出附加到文件的数据pv- 测量通过管道的数据流> /dev/null- 标准输出被丢弃
Note: sometimes pvmay be not preinstalled
注意：有时pv可能没有预装
I hope this will help somebody :)
我希望这会帮助某人:)
回答by Osiris
For fast detailed growth watching of a file, every 0.1 second:
对于文件的快速详细增长观察，每 0.1 秒：
watch -n 0.1 "ls -l /mnt/some/file | awk '{print $5}' | sed -re ' :rep ; s/([0-9])([0-9]{3})($|[^0-9])/,/ ; t rep '"
This will produce something like 62,673,539,072.
这将产生类似 62,673,539,072 的结果。
回答by Punja Solanki
You can perform this like that:
你可以这样执行：
while true; do
du -s **file_or_directory**
sleep **time_interval**
done
回答by kvantour
The usage of watchis correct, but the usage of lsI would avoid. I would recommend the usage of stator du, but this depends on what you want.
的用法watch是正确的，但ls我会避免使用。我会推荐使用stator du，但这取决于你想要什么。
du:If you want the space occupied on your drivestat:If you want the number of bytes your file contains (how many bytes can I read from the file)
du:如果你想占用你的驱动器上的空间stat：如果您想要文件包含的字节数（我可以从文件中读取多少字节）
Imagine working with a compressed file system, or with processing sparse files, internal fragmentation, indirect blocks ...
想象一下使用压缩文件系统，或者处理稀疏文件、内部碎片、间接块......
For both cases, the result would be:
对于这两种情况，结果都是：
$ watch -n 5 'stat --printf "%s\n" file'
$ watch -n 5 'du -B1 file'
Both results can actually be obtained in a single command with stat:
这两个结果实际上都可以在单个命令中获得stat：
$ watch -n 5 'stat --printf "%s %b %B\n" file'
The product of the last two columns is the result of du.
最后两列的乘积是 的结果du。
回答by Marcelo Pacheco
#!/bin/bash
# Watch File Size and Growth
# Author: Marcelo Pacheco - [email protected]
# Syntax: watchfilesize filetomonitor
nm=""
while true
do
sz=$(stat -c %s "$nm")
sleep 1m
sz1=$(stat -c %s "$nm")
echo Growth: $(((sz1-sz)/1024))KB/min Size: $((sz1/1024/1024))MB
sz=$sz1
done
