oracle PLS-00103：遇到符号“;” 当期待以下之一时：
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/20058685/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
PLS-00103: Encountered the symbol ";" when expecting one of the following:
提问by Moh-ksa Madinah
what is wrong in my code
我的代码有什么问题
SQL> declare
2 mark number :=50;
3 begin
4 mark :=& mark;
5 if (mark between 85 and 100)
6 then
7 dbms_output.put_line('mark is A ');
8 else if (mark between 50 and 65) then
9 dbms_output.put_line('mark is D ');
10 else if (mark between 66 and 75) then
11 dbms_output.put_line('mark is C ');
12 else if (mark between 76 and 84) then
13 dbms_output.put_line('mark is B');
14 else
15 dbms_output.put_line('mark is F');
16 end if;
17 end;
18 /
Enter value for mark: 65
old 4: mark :=& mark;
new 4: mark :=65;
end;
*
ERROR at line 17: ORA-06550: line 17, column 4: PLS-00103: Encountered the symbol ";" when expecting one of the following: if
第 17 行错误：ORA-06550：第 17 行，第 4 列：PLS-00103：遇到符号“；” 当期待以下之一时：如果
回答by Richard
The problem is that the elseand ifare two operators here. Since you open a new 'if' you need a corresponding 'end if'.
问题是这里的else和if是两个运算符。由于您打开了一个新的“if”，因此您需要一个相应的“end if”。
Thus:
因此：
declare
mark number :=50;
begin
mark :=& mark;
if (mark between 85 and 100) then
dbms_output.put_line('mark is A ');
else
if (mark between 50 and 65) then
dbms_output.put_line('mark is D ');
else
if (mark between 66 and 75) then
dbms_output.put_line('mark is C ');
else
if (mark between 76 and 84) then
dbms_output.put_line('mark is B');
else
dbms_output.put_line('mark is F');
end if;
end if;
end if;
end if;
end;
/
Alternatively you can use elsif:
或者，您可以使用 elsif：
declare
mark number :=50;
begin
mark :=& mark;
if (mark between 85 and 100)
then
dbms_output.put_line('mark is A ');
elsif (mark between 50 and 65) then
dbms_output.put_line('mark is D ');
elsif (mark between 66 and 75) then
dbms_output.put_line('mark is C ');
elsif (mark between 76 and 84) then
dbms_output.put_line('mark is B');
else
dbms_output.put_line('mark is F');
end if;
end;
/
回答by Dulith De Costa
The IF statement has these forms in PL/SQL:
IF 语句具有以下形式PL/SQL：
IF THEN
IF THEN ELSE
IF THEN ELSIF
You have used elseifwhich in terms of PL/SQL is wrong. That need to be replaced with ELSIF.
你用过elseifwhich 就 PL/SQL 而言是错误的。那需要替换为ELSIF.
DECLARE
mark NUMBER :=50;
BEGIN
mark :=& mark;
IF (mark BETWEEN 85 AND 100) THEN
dbms_output.put_line('mark is A ');
elsif (mark BETWEEN 50 AND 65) THEN
dbms_output.put_line('mark is D ');
elsif (mark BETWEEN 66 AND 75) THEN
dbms_output.put_line('mark is C ');
elsif (mark BETWEEN 76 AND 84) THEN
dbms_output.put_line('mark is B');
ELSE
dbms_output.put_line('mark is F');
END IF;
END;
/
