Python 从用户获取数字并打印最大值和最小值（不使用内置函数）
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get numbers from user & print maximum and minimum (w/o using built-in function)
提问by digging
I'm reviewing a python exercise which does the following :
我正在执行以下操作的 python 练习：
reads list of numbers til "done" gets entered.
When "done" is inputted, print largest and smallest of the numbers.
And it should be without directly usingthe built-in functions, max() and min().
读取数字列表直到输入“完成”。
当输入“done”时，打印最大和最小的数字。
它应该不直接使用内置函数 max() 和 min()。
Here is my source. Traceback says, "'float' object is not iterable"
这是我的来源。Traceback 说，“'float' 对象不可迭代”
I think my errors are coming from not using the list properly to calculate smallest and largest. Any tips and help will be greatly appreciated!
我认为我的错误来自没有正确使用列表来计算最小和最大。任何提示和帮助将不胜感激！
while True:
inp = raw_input('Enter a number: ')
if inp == 'done' :
break
try:
num = float(inp)
except:
print 'Invalid input'
continue
numbers = list(num)
minimum = None
maximum = None
for num in numbers :
if minimum == None or num < minimum :
minimum = num
for num in numbers :
if maximum == None or maximum < num :
maximum = num
print 'Maximum:', maximum
print 'Minimum:', minimum
Thank you!
谢谢！
回答by Frank
With num = float(inp)you only assign a single number and overwrite it each time a new one is assigned. You have to create the list first, then add numbers to it each time. Something like this:
有了num = float(inp)你只分配一个号码，每一个新的分配时间覆盖它。您必须先创建列表，然后每次都添加数字。像这样的东西：
nums = []
while True:
...
nums.append(float(inp))
回答by Mike DeSimone
You shouldn't need a list. You should only need to keep track of the current minimum and maximum as you go.
你不应该需要一个列表。您应该只需要随时跟踪当前的最小值和最大值。
minimum = None
maximum = None
while True:
inp = raw_input('Enter a number: ')
if inp == 'done':
break
try:
num = float(inp)
except:
print 'Invalid input'
continue
if minimum is None or num < minimum:
minimum = num
if maximum is None or num > maximum:
maximum = num
print 'Maximum:', maximum
print 'Minimum:', minimum
回答by RakeshKirola
input_set = []
input_num = 0
while (input_num >= 0):
input_num = int(input("Please enter a number or -1 to finish"))
if (input_num < 0):
break
input_set.append(input_num)
print(input_set)
largest = input_set[0]
for i in range(len(input_set)):
if input_set[i] > largest:
greatest = input_set[i]
print("Largest number is", greatest)
smallest = input_set[0]
for i in range(len(input_set)):
if input_set[i] < largest:
smallest = input_set[i]
print("Smallest number is", smallest)
