javascript 如何使用 getTime() 从两个日期正确计算 JS 中的剩余时间？
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How to properly calculate remaining time in JS using getTime() from the two dates?
提问by craftApprentice
I'm trying to calculate remaining time (ex: 10 years, 2 months and 10 days from today(2014/03/02) in JS using this function:
我正在尝试使用此函数在 JS 中计算剩余时间（例如：从今天（2014/03/02）算起的 10 年、2 个月和 10 天：
var d2 = new Date(2024, 3, 12);
var d1 = new Date();
var d0 = new Date(1970, 0, 1);
var diff = new Date(d2.getTime() - (d1.getTime() + d0.getTime() ) );
var years = diff.getFullYear();
var months = diff.getMonth();
var days = diff.getDay();
alert("remaining time = " + years + " years, " + months + " months, " + days + " days.");
But instead of get the 10 years difference, I got 1980 years difference (though the days difference I understand that are produced buy the variation of days in months and years):
但是，我得到了 1980 年的差异，而不是 10 年的差异（尽管我理解的天数差异购买了以月和年为单位的天数变化）：
Is it possible to perform this "remaining time" operation using this strategy? If so, how to get the expected result?
是否可以使用此策略执行此“剩余时间”操作？如果是这样，如何得到预期的结果？
Here the function in a JS shell: jsfiddle.net/3ra6c/
这里是 JS shell 中的函数：jsfiddle.net/3ra6c/
采纳答案by Xotic750
As I explained, Dateis not equipped with such functions and you have to do the math yourself. You can get the milliseconds difference between two dates, but then it's down to doing the math to represent that as you wish.
正如我所解释的，Date没有配备这样的功能，你必须自己做数学。您可以获得两个日期之间的毫秒差异，但是接下来就需要根据自己的意愿进行数学运算来表示它了。
An example of using moment.js, loaded with require.js, with humanized approximations.
使用moment.js，加载require.js，具有人性化近似值的示例。
Javascript
Javascript
require.config({
paths: {
moment: 'http://momentjs.com/downloads/moment.min'
}
});
require(['moment'], function (moment) {
var x = moment(new Date(2024, 3, 12)).from(new Date());
console.log(x);
});
Output
输出
in 10 years
On jsFiddle
Look at their docs to see how you can humanize the output, you may want a little more detail.
查看他们的文档以了解如何将输出人性化，您可能需要更多细节。
回答by craftApprentice
I find herethe solution I was looking for:
我在这里找到了我正在寻找的解决方案：
var date1 = new Date();
var date2 = new Date(2015, 2, 2);
var diff = new Date(date2.getTime() - date1.getTime());
var years = diff.getUTCFullYear() - 1970; // Gives difference as year
var months = diff.getUTCMonth(); // Gives month count of difference
var days = diff.getUTCDate()-1; // Gives day count of difference
alert("remaining time = " + years + " years, " + months + " months, " + days + " days.");
And it seems to work very well!
它似乎工作得很好！
回答by Martin Diphoorn
var diff = new Date(d2.getTime() - (d1.getTime() + d0.getTime() ) )
var diff = new Date(d2.getTime() - (d1.getTime() + d0.getTime() ) )
Why do you add d0? Try to remove it.
为什么要加d0？尝试将其删除。
