Laravel 4 无法捕获异常
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原文地址: http://stackoverflow.com/questions/14309262/
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Laravel 4 not able to catch Exception
提问by duality_
I have tried to isolate this problem (to produce it outside my app), but I can't.
我试图隔离这个问题（在我的应用程序之外产生它），但我不能。
try {
$has_cache = Cache::has($cache_key);
}
catch (DecryptException $e) {
echo "No biggie";
exit;
}
I also tried with a catch (Exception $e), the same thing happens.
我也试过 a catch (Exception $e)，同样的事情发生了。
Using this code, I get a DecryptException in the second line. How can this happen, it's in the try block?
使用此代码，我在第二行得到一个 DecryptException。这怎么会发生，它在 try 块中？
Like I said, I tried to do the same on a clean project, but there it caught the exception, so I'm asking where could I have messed something up.
就像我说的，我试图在一个干净的项目上做同样的事情，但在那里它发现了异常，所以我问我在哪里搞砸了。
回答by dualed
If your application is namespaced, you would need to use
如果您的应用程序是命名空间的，则需要使用
catch(\Exception $e);
// or preferably
catch(\RuntimeException $e);
likewise, I think the DecryptExceptionyou are trying to catch is namespaced in Illuminate\Encryptionso you'd need
同样，我认为DecryptException您要捕获的名称是命名空间的，Illuminate\Encryption因此您需要
catch(\Illuminate\Encryption\DecryptException)
// or use "use" somewhere before the try/catch
use \Illuminate\Encryption\DecryptException
Keep in mindthat Laravel 4 is still alphaor pre-beta(apparently they are not sure themselves), so it is in no way stable and probably not the best choice for production.
请记住，Laravel 4 仍然是alpha或pre-beta（显然他们自己不确定），所以它绝不是稳定的，也可能不是生产的最佳选择。
回答by Abhishek Sachan
For laravel 5.1 you should write(generally at start of the file with other use statements):
对于laravel 5.1，您应该编写（通常在文件开头使用其他使用语句）：
use Illuminate\Contracts\Encryption\DecryptException;
Before catch statement:
在 catch 语句之前：
try {
$data = \Crypt::decrypt($key);
} catch (DecryptException $e) {
echo 'caught exception';
exit();
}
Ref: https://laravel.com/docs/5.1/encryption- under "Decrypting A Value"
参考：https: //laravel.com/docs/5.1/encryption- 在“解密值”下
May be helpful for others.
可能对其他人有帮助。
