我可以向 bash 函数传递多少个参数？
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How many arguments can I pass to a bash function?
提问by zedoo
Is the number of arguments that a bash function can accept limited?
bash 函数可以接受的参数数量是否有限？
采纳答案by unwind
The bash manualsays:
在bash的手册说：
There is no maximum limit on the size of an array, nor any requirement that members be indexed or assigned contiguously.
对数组的大小没有最大限制，也没有对成员连续索引或分配的任何要求。
I believe this applies, since function arguments are presented as an array.
我相信这适用，因为函数参数以数组的形式呈现。
回答by Paused until further notice.
To access arguments in a function, you can iterate over them:
要访问函数中的参数，您可以遍历它们：
foo () {
for arg # "in $@" is implied
do
echo $arg
done
}
or
或者
bar () {
while [ ]
do
echo
shift
done
}
or to access specific arguments:
或访问特定参数：
baz () {
# for arguments above you have to use curly braces
echo ${121375}
}
回答by Michael Kropat
The number is fairly large:
数量相当大：
$ display_last_arg() { echo "${@: -1}"; }
$ getconf ARG_MAX
262144
$ display_last_arg {1..262145}
262145
$ echo $(( 2**18 )) $(( 2**20 ))
262144 1048576
$ display_last_arg {1..1048576}
1048576
As you can see, it's larger than the kernel ARG_MAX limit, which makes sense since Bash does not call execve(2)to invoke Bash-defined functions.
如您所见，它大于内核 ARG_MAX limit，这是有道理的，因为 Bash 不会调用execve(2)来调用 Bash 定义的函数。
I get mallocfailures if I try to perform Bash sequence expansion ({1..NUM}) in the 2^32 range, so there is a hard limit somewhere (might vary on your machine), but Bash is so slow once you get above 2^20 arguments, that you will hit a performance limit well before you hit a hard limit.
malloc如果我尝试{1..NUM}在 2^32 范围内执行 Bash 序列扩展 ( )，我会失败，因此某处存在硬限制（可能因您的机器而异），但是一旦超过 2^20 个参数，Bash 就会变得很慢，那在达到硬限制之前，您将很早就达到性能限制。
