java 尝试设置 spring servlet 时出现“警告 org.springframework.web.servlet.PageNotFound - 未找到带有 URI 的 HTTP 请求的映射...”
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Getting "WARN org.springframework.web.servlet.PageNotFound - No mapping found for HTTP request with URI ..." when trying to setup spring servlet
提问by OneTwo
I am trying to setup a Spring MVC project. I have added a dispatcher servlet, a jsp and setup the web.xml file. But I keep getting
我正在尝试设置一个 Spring MVC 项目。我添加了一个调度程序 servlet、一个 jsp 并设置了 web.xml 文件。但我不断得到
WARN org.springframework.web.servlet.PageNotFound - No mapping found for HTTP request with URI [/safesite/WEB-INF/jsp/hello.jsp] in DispatcherServlet with name 'HelloWeb'
警告 org.springframework.web.servlet.PageNotFound - 在 DispatcherServlet 中找不到名称为“HelloWeb”的带有 URI [/safesite/WEB-INF/jsp/hello.jsp] 的 HTTP 请求的映射
Here's my web.xml
这是我的 web.xml
...
<context-param>
<description>Vaadin production mode</description>
<param-name>productionMode</param-name>
<param-value>true</param-value>
</context-param>
<!-- To load the Spring context -->
<listener>
<listener-class>org.activiti.explorer.servlet.WebConfigurer</listener-class>
</listener>
<!-- To allow session-scoped beans in Spring -->
<listener>
<listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
</listener>
<filter>
<filter-name>UIFilter</filter-name>
<filter-class>org.activiti.explorer.filter.ExplorerFilter</filter-class>
</filter>
<filter>
<filter-name>JSONPFilter</filter-name>
<filter-class>org.activiti.explorer.servlet.JsonpCallbackFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>UIFilter</filter-name>
<url-pattern>/o/*</url-pattern>
</filter-mapping>
<filter-mapping>
<filter-name>JSONPFilter</filter-name>
<url-pattern>/service/*</url-pattern>
</filter-mapping>
<servlet>
<servlet-name>Vaadin Application Servlet</servlet-name>
<servlet-class>org.activiti.explorer.servlet.ExplorerApplicationServlet</servlet-class>
<init-param>
<param-name>widgetset</param-name>
<param-value>org.activiti.explorer.CustomWidgetset</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>Vaadin Application Servlet</servlet-name>
<url-pattern>/ui/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Vaadin Application Servlet</servlet-name>
<url-pattern>/VAADIN/*</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>HelloWeb</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>HelloWeb</servlet-name>
<url-pattern>*.jsp</url-pattern>
</servlet-mapping>
<!-- Session timeout on one day -->
<session-config>
<session-timeout>480</session-timeout>
</session-config>
And here is my HelloWeb-servlet.xml
这是我的 HelloWeb-servlet.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="org.activiti.explorer.controller" />
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass"
value="org.springframework.web.servlet.view.JstlView" />
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
My HelloController
我的HelloController
package org.activiti.explorer.controller;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;
/**
*
* @author Fionn
*/
@Controller
public class HelloController {
@RequestMapping("/hello")
public ModelAndView helloWorld() {
String message = "<br><div align='center'>"
+ "<h3>********** Hello World, Spring MVC Tutorial</h3>This message is comming from CrunchifyHelloWorld.java **********<br><br>";
return new ModelAndView("hello", "message", message);
}
}
And my hello.jsp
还有我的 hello.jsp
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<%@taglib uri="http://www.springframework.org/tags" prefix="spring"%>
<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
<%@ taglib prefix="form" uri="http://www.springframework.org/tags/form" %>
<%@page trimDirectiveWhitespaces="true" %>
<!DOCTYPE html>
<html>
<head>
<title>Hello Spring MVC</title>
</head>
<body>
I can't figure this one out so any help would be greatly appreciated.
我无法弄清楚这一点，因此任何帮助将不胜感激。
回答by Master Slave
You seem to be missing the <mvc:annotation-driven />
你似乎错过了 <mvc:annotation-driven />
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd">
<!-- Enables the Spring MVC @Controller programming model -->
<mvc:annotation-driven />
<context:component-scan base-package="org.activiti.explorer.controller" />
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass"
value="org.springframework.web.servlet.view.JstlView" />
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
</beans>
note that I've removed the version from the xsd files, this means that it will use the schema from your jar files (and there will be a validation error in case of incompatibilty)
请注意，我已经从 xsd 文件中删除了版本，这意味着它将使用您的 jar 文件中的架构（并且在不兼容的情况下会出现验证错误）
after @Nikolay's comment, I've also noticed an error in your mapping (note that you still need the annotation-driven element), you should either change the mapping in your controller to
在@Nikolay 发表评论之后，我还注意到您的映射中有一个错误（请注意，您仍然需要注释驱动的元素），您应该将控制器中的映射更改为
@RequestMapping("/hello.jsp")
and access it via
并通过访问它
/safesite/hello.jsp
OR, more common, change the servlet mapping to
或者，更常见的是，将 servlet 映射更改为
<servlet-mapping>
<servlet-name>HelloWeb</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
and access as Nikolay said so /safesite/hello
并像尼古拉所说的那样访问 /safesite/hello
回答by Simon L
I had a similar issue before which was very confusing, after a series of tests, I found it's the url-pattern for the DispatcherServlet. Be cautious when you use the asterisk for wildcard match which might lead to unexpected behavior, and it's just safe to start from root "/" or your custom servlet context path "/foo/"
我之前也遇到过类似的问题，很困惑，经过一系列测试，我发现这是 DispatcherServlet 的 url-pattern。当您使用星号进行通配符匹配时要小心，这可能会导致意外行为，从根“/”或您的自定义 servlet 上下文路径“/foo/”开始是安全的
Try the following.
请尝试以下操作。
<servlet-mapping>
<servlet-name>HelloWeb</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>回答by Alon Asulin
I got that error when i migrated/updated from Spring framework 3.X to 4.X and using json (through Hymanson2) as returned object and got the error above.
当我从 Spring 框架 3.X 迁移/更新到 4.X 并使用 json（通过 Hymanson2）作为返回对象并得到上述错误时，我遇到了该错误。
To solve that you should add
要解决该问题，您应该添加
<bean class="org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerAdapter">
<property name="messageConverters">
<list>
<bean class="org.springframework.http.converter.StringHttpMessageConverter">
<property name="supportedMediaTypes" value = "text/plain;charset=UTF-8"/>
</bean>
</list>
</property>
</bean>
<bean class="org.springframework.web.accept.ContentNegotiationManagerFactoryBean">
<property name="mediaTypes">
<map>
<entry key="json" value="application/json"/>
</map>
</property>
</bean>
<bean class="org.springframework.web.servlet.view.json.MappingHymanson2JsonView">
<property name="contentType" value="application/json"/>
</bean>
To XXX-servlet.xml file
到 XXX-servlet.xml 文件
And on the code you should use MappingHymanson2JsonView as return value for example :
在代码中，您应该使用 MappingHymanson2JsonView 作为返回值，例如：
@RequestMapping("/user")
MappingHymanson2JsonView user() {
MappingHymanson2JsonView view = new MappingHymanson2JsonView();
view.setExtractValueFromSingleKeyModel(true);
view.addStaticAttribute("user", new User("Sébastien", "Deleuze"));
view.setPrefixJson(true);
return view;
}
for more examples look here: http://www.programcreek.com/java-api-examples/index.php?api=org.springframework.web.servlet.view.json.MappingHymanson2JsonView
更多示例请看这里：http: //www.programcreek.com/java-api-examples/index.php?api=org.springframework.web.servlet.view.json.MappingHymanson2JsonView
