C++ Qt：将 QString 转换为十六进制
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Qt: Convert QString to Hexadecimal
提问by Jafuentes
I know this is a very basic question but I'm newbie in Qt and I don't know to do it. I'm trying to convert a QString value (like "AA110011") to hexadecimal. I would like to obtain 0xaa110011. I've tried with this code:
我知道这是一个非常基本的问题，但我是 Qt 的新手，我不知道该怎么做。我正在尝试将 QString 值（如“AA110011”）转换为十六进制。我想获得 0xaa110011。我试过这个代码：
QByteArray b = aString.toUtf8();
for (int i = 0; i < b.length(); i++ )
{
if ( b[i] >= 65 && b[i] <= 70 )
{
b[i] = b[i] - 55;
}
else if (b[i] >= 48 && b[i] <= 57)
{
b[i] = b[i] - 48;
}
}
I obtain in the Memory at Vairable "[0]" the value 0a 0a 01 01 00 00 01 01 and I don't know how could I obtain aa 11 00 11.
我在内存变量“[0]”中获得了值 0a 0a 01 01 00 00 01 01，但我不知道如何获得 aa 11 00 11。
Could you help me? thanks.
你可以帮帮我吗？谢谢。
回答by Frank Osterfeld
Try QString::toInt, QString::toUInt, QString::toLongetc., for example:
尝试的QString :: toInt，QString的:: toUInt，QString的:: toLong等，例如：
const QString str = QLatin1String("AA110011");
bool ok;
const unsigned int parsedValue = str.toUInt(&ok, 16);
if (!ok) {
//Parsing failed, handle error here
}
qDebug() << parsedValue;
The second argument is the base, 16 in this case for hexadecimal.
第二个参数是基数，在这种情况下是十六进制的 16。
This solution will work if your string fits into a unsigned long long or shorter - it will not work if you want to convert arbitrarily long strings that way.
如果您的字符串适合 unsigned long long 或更短的字符串，则此解决方案将起作用 - 如果您想以这种方式转换任意长的字符串，则该解决方案将不起作用。
回答by Jimit Rupani
Just use this and thank me later.
只需使用它，稍后再感谢我。
QString prgName = query.value(1).toString();
prgName.toLatin1().toHex();
