jQuery jquery反向数组
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jquery reverse array
提问by ceasar
I have the following snippet which returns some youtube id's. Now I want to reverse the output (because now it is the last first)
我有以下代码段，它返回一些 youtube id。现在我想反转输出（因为现在它是最后一个）
if (options.slideshow) {
var links = [];
var $lis = holder.parents('#yt_holder').find('li');
var $as = $lis.children('a');
for(var count = $lis.length-1, i = count; i >= 0; i--){
links.push(youtubeid($as[i].href));
}
slideshow = '&playlist=' + links + '';
alert(slideshow);
}
I tried .reverse() but some items seems to be missing then
我试过 .reverse() 但有些项目似乎丢失了
links.reverse().push(youtubeid($as[i].href));
Any help will be appreciated. Ceasar
任何帮助将不胜感激。凯撒
回答by Alnitak
You should reverse the list afteryou've accumulated it:
您应该在累积后反转列表：
for ( ... ) {
...
}
links = links.reverse();
but it would be better to just put the elements into the array in the right order in the first place.
但最好首先将元素按正确的顺序放入数组中。
回答by Jason Gennaro
Try adding the videos in the reverse order, so instead of this
尝试以相反的顺序添加视频，而不是这样
for(var count = $lis.length-1, i = count; i >= 0; i--){
links.push(youtubeid($as[i].href));
}
Do this
做这个
for(var i = 0, count = $lis.length; i < count; i++){
links.push(youtubeid($as[i].href));
}
回答by Aakash Dhoundiyal
Hi you after reversing the links array ,you have to assign it to other array and hence it will work.
嗨，在反转链接数组后，您必须将其分配给其他数组，因此它会起作用。
var slideshow = [];
slideshow = links.reverse();
