string 如何在PowerShell中使用运算符“-replace”将文本字符串替换为特殊字符并成功替换
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How to use operator '-replace' in PowerShell to replace strings of texts with special characters and replace successfully
提问by user2957157
I have a script where I am basically doing a find and replace on several strings of text. The first couple of strings work, but when I do the account keys, they do not. How can I fix this problem?
我有一个脚本，我基本上是在其中对几个文本字符串进行查找和替换。前几个字符串有效，但是当我处理帐户密钥时，它们不起作用。我该如何解决这个问题？
Here is the script:
这是脚本：
Get-ChildItem "[FILEPATH]" -recurse |
Foreach-Object {
$c = ($_ | Get-Content)
$c = $c -replace 'abt7d9epp4','w2svuzf54f'
$c = $c -replace 'AccountName=adtestnego','AccountName=zadtestnego'
$c = $c -replace 'AccountKey=eKkij32jGEIYIEqAR5RjkKgf4OTiMO6SAyF68HsR/Zd/KXoKvSdjlUiiWyVV2+OUFOrVsd7jrzhldJPmfBBpQA==','DdOegAhDmLdsou6Ms6nPtP37bdw6EcXucuT47lf9kfClA6PjGTe3CfN+WVBJNWzqcQpWtZf10tgFhKrnN48lXA=='
[IO.File]::WriteAllText($_.FullName, ($c -join "`r`n"))
}
回答by Adil Hindistan
'-replace' does a regex search and you have special characters in that last one (like +) So you might use the non-regex replace version like this:
'-replace' 进行正则表达式搜索，最后一个中有特殊字符（如 +），因此您可以使用非正则表达式替换版本，如下所示：
$c = $c.replace('AccountKey=eKkij32jGEIYIEqAR5RjkKgf4OTiMO6SAyF68HsR/Zd/KXoKvSdjlUiiWyVV2+OUFOrVsd7jrzhldJPmfBBpQA==','DdOegAhDmLdsou6Ms6nPtP37bdw6EcXucuT47lf9kfClA6PjGTe3CfN+WVBJNWzqcQpWtZf10tgFhKrnN48lXA==')
回答by mjolinor
If you've got V3, you can take advantage of auto-enumeration, the -Raw switch in Get-Content, and some of the new line contiunation syntax to simply it to this, using the string .replace() method instead of the -replace operator:
如果你有 V3，你可以利用自动枚举、Get-Content 中的 -Raw 开关和一些新的行连续语法来简单地使用字符串 .replace() 方法而不是-替换运算符：
(Get-ChildItem "[FILEPATH]" -recurse).FullName |
Foreach-Object {
(Get-Content $_ -Raw).
Replace('abt7d9epp4','w2svuzf54f').
Replace('AccountName=adtestnego','AccountName=zadtestnego').
Replace('AccountKey=eKkij32jGEIYIEqAR5RjkKgf4OTiMO6SAyF68HsR/Zd/KXoKvSdjlUiiWyVV2+OUFOrVsd7jrzhldJPmfBBpQA==','AccountKey=DdOegAhDmLdsou6Ms6nPtP37bdw6EcXucuT47lf9kfClA6PjGTe3CfN+WVBJNWzqcQpWtZf10tgFhKrnN48lXA==') |
Set-Content $_
}
Using the .replace() method uses literal strings for the replaced text argument (not regex), so you don't need to worry about escaping regex metacharacters in the text-to-replace argument.
使用 .replace() 方法将文字字符串用于替换文本参数（不是正则表达式），因此您无需担心在 text-to-replace 参数中转义正则表达式元字符。
回答by Anthony Neace
In your example, you prepended your source string with AccountKey=but not your target string.
在您的示例中，您在源字符串之前添加了AccountKey=目标字符串，但未添加目标字符串。
$c = $c -replace 'AccountKey=eKkij32jGEIYIEqAR5RjkKgf4OTiMO6SAyF68HsR/Zd/KXoKvSdjlUiiWyVV2+OUFOrVsd7jrzhldJPmfBBpQA==','AccountKey=DdOegAhDmLdsou6Ms6nPtP37bdw6EcXucuT47lf9kfClA6PjGTe3CfN+WVBJNWzqcQpWtZf10tgFhKrnN48lXA=='
By not including that in the target string, the resulting string will remove AccountKey=instead of replacing it. You correctly do this with the AccountName=example, which seems to support this conclusion since it is not giving you any problems. If you really mean to have that prepended, then this may resolve your issue.
通过不在目标字符串中包含它，生成的字符串将被删除AccountKey=而不是替换它。你用这个AccountName=例子正确地做到了这一点，它似乎支持这个结论，因为它没有给你任何问题。如果你真的想把它放在前面，那么这可能会解决你的问题。
