将文件从 Javascript 上传到 PHP
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Pass file from Javascript upload to PHP
提问by ebidel
I'm working on a script to let the user upload a file and sees a upload status and the file is then saved on the server.
我正在编写一个脚本，让用户上传文件并查看上传状态，然后将文件保存在服务器上。
The problem is that I cannot use the php api. So I was thinking to upload the file with javascript where I can easly get the upload status but then I want to pass the file to php and save it.
问题是我不能使用 php api。所以我想用javascript上传文件，我可以很容易地获得上传状态，但我想将文件传递给php并保存它。
Is this possible?
这可能吗？
This is the javascript code to upload.
这是要上传的javascript代码。
<!DOCTYPE html>
<html>
<head >
<title>Upload Files using XMLHttpRequest</title>
<script type="text/javascript">
function fileSelected() {
var file = document.getElementById('fileToUpload').files[0];
if (file) {
var fileSize = 0;
if (file.size > 1024 * 1024)
fileSize = (Math.round(file.size * 100 / (1024 * 1024)) / 100).toString() + 'MB';
else
fileSize = (Math.round(file.size * 100 / 1024) / 100).toString() + 'KB';
document.getElementById('fileName').innerHTML = 'Name: ' + file.name;
document.getElementById('fileSize').innerHTML = 'Size: ' + fileSize;
document.getElementById('fileType').innerHTML = 'Type: ' + file.type;
}
}
function uploadFile() {
var fd = new FormData();
fd.append("fileToUpload", document.getElementById('fileToUpload').files[0]);
var xhr = new XMLHttpRequest();
xhr.upload.addEventListener("progress", uploadProgress, false);
xhr.addEventListener("load", uploadComplete, false);
xhr.addEventListener("error", uploadFailed, false);
xhr.addEventListener("abort", uploadCanceled, false);
xhr.open("POST", "UploadHandler.ashx");
xhr.send(fd);
}
function uploadProgress(evt) {
if (evt.lengthComputable) {
var percentComplete = Math.round(evt.loaded * 100 / evt.total);
document.getElementById('progressNumber').innerHTML = percentComplete.toString() + '%';
document.getElementById('prog').value = percentComplete;
}
else {
document.getElementById('progressNumber').innerHTML = 'unable to compute';
}
}
function uploadComplete(evt) {
/* This event is raised when the server send back a response */
alert(evt.target.responseText);
}
function uploadFailed(evt) {
alert("There was an error attempting to upload the file.");
}
function uploadCanceled(evt) {
alert("The upload has been canceled by the user or the browser dropped the connection.");
}
</script>
</head>
<body>
<form id="form1">
<div>
<label for="fileToUpload">
Select a File to Upload</label>
<input type="file" name="fileToUpload[]" id="fileToUpload" onchange="fileSelected();" />
</div>
<div id="fileName">
</div>
<div id="fileSize">
</div>
<div id="fileType">
</div>
<div>
<input type="button" onclick="uploadFile()" value="Upload" />
</div>
<div id="progressNumber">
</div>
<progress id="prog" value="0" max="100.0"></progress>
</form>
</body>
</html>
回答by ebidel
回答by Mahdi
Make an AJAX request to a PHP file, send the uploaded file properties like name, etc. and let it open that, move that, rename that or whatever needed. It should works, huh?
向 PHP 文件发出 AJAX 请求，发送上传的文件属性，如名称等，让它打开、移动、重命名或任何需要的。应该有效吧？
did I understood your question correctly?
我是否正确理解了您的问题？
Sample Code:
示例代码：
In Javascript:
在 JavaScript 中：
// xhr
var http = new XMLHttpRequest();
var url = "file_handler.php";
var file_data = "name=mypic.jpg&size=123&othe=etc";
http.open("POST", url, true);
// headers
http.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
http.setRequestHeader("Content-length", file_data.length);
http.setRequestHeader("Connection", "close");
http.onreadystatechange = function() {
if(http.readyState == 4 && http.status == 200) {
alert(http.responseText);
}
}
http.send(file_data);
In file_handler.php:
在file_handler.php：
// file data
$file_data = $_POST['file_data'];
// working on the file
$temp_dir = 'usr/upload/';
$new_dir = 'usr/photos/';
// new unique name
$new_name = time() . '_' . $file_data['name'];
// copy?
if (copy($temp_dir . $file_data['name'], $new_dir . $new_name)) {
unlink($temp_dir . $file_data['name']);
}
// rename?
rename($temp_dir . $file_data['name'], $temp_dir . $new_name);
// delete old file?
unlink($temp_dir . $file_data['name']);
// do whatever else needed here ...
// echo some JSON data to interact with your client-side JS code, maybe ...
