测试字符串是否包含 PHP 中的单词？
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Test if a string contains a word in PHP?
提问by Lucas Matos
In SQL we have NOT LIKE %string%
在 SQL 中，我们有 NOT LIKE %string%
I need to do this in PHP.
我需要在 PHP 中执行此操作。
if ($string NOT LIKE %word%) { do something }
I think that can be done with strpos()
我认为可以做到 strpos()
But can't figure out how…
但是想不通怎么办……
I need exactly that comparission sentence in valid PHP.
我在有效的 PHP 中完全需要那个比较语句。
if ($string NOT LIKE %word%) { do something }
回答by Marc B
if (strpos($string, $word) === FALSE) {
... not found ...
}
Note that strpos()is case sensitive, if you want a case-insensitive search, use stripos()instead.
请注意，这strpos()是区分大小写的，如果您想要不区分大小写的搜索，请stripos()改用。
Also note the ===, forcing a strict equality test. strpos CAN return a valid 0if the 'needle' string is at the start of the 'haystack'. By forcing a check for an actual boolean false (aka 0), you eliminate that false positive.
还要注意===, 强制进行严格的相等测试。0如果 'needle' 字符串位于 'haystack' 的开头，strpos 可以返回一个有效值。通过强制检查实际布尔值 false（又名 0），您可以消除误报。
回答by TimWolla
Use strpos. If the string is not found it returns false, otherwise something that is not false. Be sure to use a type-safe comparison (===) as 0may be returned and it is a falsy value:
使用strpos. 如果未找到该字符串，则返回false，否则返回false。一定要使用类型安全的比较 ( ===) ，因为它0可能会返回，它是一个假值：
if (strpos($string, $substring) === false) {
// substring is not found in string
}
if (strpos($string, $substring2) !== false) {
// substring2 is found in string
}
回答by Vishnu Sharma
<?php
// Use this function and Pass Mixed string and what you want to search in mixed string.
// For Example :
$mixedStr = "hello world. This is john duvey";
$searchStr= "john";
if(strpos($mixedStr,$searchStr)) {
echo "Your string here";
}else {
echo "String not here";
}
回答by Ganesh
use
if(stripos($str,'job')){
// do your work
}