ios 无法识别的选择器在归档数据时发送到实例（NSCoding）
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Unrecognized selector sent to instance while archiving data (NSCoding)
提问by SteBra
-(void)transformObjects:(NSMutableArray*)array key:(NSString*)key
{
NSMutableArray* archiveArray = [[NSMutableArray alloc]initWithCapacity:array.count];
for (Furniture *furniture in array) {
// The error occurs on the line below
NSData *furnitureEncodedObject = [NSKeyedArchiver archivedDataWithRootObject:furniture];
[archiveArray addObject:furnitureEncodedObject];
}
NSUserDefaults *userData = [NSUserDefaults standardUserDefaults];
[userData setObject:archiveArray forKey:key];
}
Error log:
错误日志：
2014-03-04 10:55:27.881 AppName[10641:60b] -[Furniture encodeWithCoder:]: unrecognized selector sent to instance 0x15d43350
I have no idea why do I get "unrecognized selector sent to instance" when trying to archive an object.
我不知道为什么在尝试存档对象时会收到“无法识别的选择器发送到实例”。
回答by Grzegorz Krukowski
You need to implement NSCoding protocol inside your Furniture object:
您需要在您的 Furniture 对象中实现 NSCoding 协议：
- (void)encodeWithCoder:(NSCoder *)aCoder{
[aCoder encodeObject:self.yourpoperty forKey:@"PROPERTY_KEY"];
}
-(id)initWithCoder:(NSCoder *)aDecoder{
if(self = [super init]){
self.yourpoperty = [aDecoder decodeObjectForKey:@"PROPERTY_KEY"];
}
return self;
}
Basically you specify what should be written (encoded) and read from a file (decoded). Usually for each property you want to store in a file, you make same as I did here in an example.
基本上，您指定应该写入（编码）和从文件中读取（解码）的内容。通常对于您想要存储在文件中的每个属性，您可以像我在示例中所做的那样进行设置。
回答by Zorayr
You'll need to implement NSCoding- here is an example with an object called SNStockthat has two string properties, tickerand name:
您需要实现NSCoding- 这是一个名为对象的示例，该对象SNStock具有两个字符串属性，ticker并且name：
import Foundation
class SNStock: NSObject, NSCoding
{
let ticker: NSString
let name: NSString
init(ticker: NSString, name: NSString)
{
self.ticker = ticker
self.name = name
}
//MARK: NSCoding
required init(coder aDecoder: NSCoder) {
self.ticker = aDecoder.decodeObjectForKey("ticker") as! NSString
self.name = aDecoder.decodeObjectForKey("name") as! NSString
}
func encodeWithCoder(aCoder: NSCoder) {
aCoder.encodeObject(ticker, forKey: "ticker")
aCoder.encodeObject(name, forKey: "name")
}
//MARK: NSObjectProtocol
override func isEqual(object: AnyObject?) -> Bool {
if let object = object as? SNStock {
return self.ticker == object.ticker &&
self.name == object.name
} else {
return false
}
}
override var hash: Int {
return ticker.hashValue
}
}
回答by Hardik Thakkar
For Swift 4.1 (tested code)
对于 Swift 4.1（测试代码）
import UIKit
import SwiftyJSON
class UserObject: NSObject, NSCoding {
var username: String? = ""
var userID: String? = ""
var user_email: String? = ""
var name: String? = ""
var age: String? = ""
var gender: String? = ""
override init() {
super.init()
}
init(dictionary: JSON) {
//User data initialize...
username = dictionary["username"].stringValue
userID = dictionary["iUserID"].stringValue
user_email = dictionary["email"].stringValue
name = dictionary["name"].stringValue
age = dictionary["age"].stringValue
gender = dictionary["gender"].stringValue
}
required public init(coder aDecoder: NSCoder) {
username = aDecoder.decodeObject(forKey: "username") as? String
userID = aDecoder.decodeObject(forKey: "iUserID") as? String
user_email = aDecoder.decodeObject(forKey: "email") as? String
name = aDecoder.decodeObject(forKey: "name") as? String
age = aDecoder.decodeObject(forKey: "age") as? String
gender = aDecoder.decodeObject(forKey: "gender") as? String
}
func encode(with aCoder: NSCoder) {
aCoder.encode(username, forKey: "username")
aCoder.encode(userID, forKey: "iUserID")
aCoder.encode(user_email, forKey: "email")
aCoder.encode(name, forKey: "name")
aCoder.encode(age, forKey: "age")
aCoder.encode(gender, forKey: "gender")
}
}
Note : NSCoding protocol is important
注意：NSCoding 协议很重要
回答by Wain
You have a custom class Furniturewhich you are trying to archive with NSKeyedArchiver. In order for this to work, the Furnitureclass needs to conform to the < NSCoding >protocol. Which means implementing the encodeWithCoder:and initWithCoder:methods.
您有一个自定义类Furniture，您正尝试使用NSKeyedArchiver. 为了使其工作，Furniture该类需要符合< NSCoding >协议。这意味着实现encodeWithCoder:和initWithCoder:方法。
Currently you don't implement these methods. You need to add them.
目前您没有实现这些方法。您需要添加它们。
回答by Benjamin Clanet
I think your Furniture class does not implement the NSCoding protocol.
我认为您的 Furniture 类没有实现 NSCoding 协议。
