Java 意外字符（'<'（代码 60））
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Unexpected character ('<' (code 60))
提问by xpagesbeast
I'm getting a weird error. This used to work. I'm not sure if it is app server, code, jvm?
我收到一个奇怪的错误。这曾经奏效。我不确定它是应用服务器、代码还是 jvm？
JVM: Java Virtual Machine initialized.
Java runtime version: pwa6480sr4fp5-20170421_01 (SR4 FP5)
JVM version: JRE 1.8.0 Windows Server 2008 R2 amd64-64 20170419_344392 (JIT enabled, AOT enabled) J9VM - R28_20170419_1004_B344392 JIT - tr.r14.java_20170419_344392 GC - R28_20170419_1004_B344392 J9CL - 20170419
```
``
JVM: Caused by:
JVM: com.fasterxml.Hymanson.core.JsonParseException: Unexpected character ('<' (code 60)): expected a valid value (number, String, array, object, 'true', 'false' or 'null')
JVM: at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@2a19861e; line: 1, column: 2]
JVM: at com.fasterxml.Hymanson.core.JsonParser._constructError(JsonParser.java:1524)
JVM: at com.fasterxml.Hymanson.core.base.ParserMinimalBase._reportError(ParserMinimalBase.java:557)
JVM: at com.fasterxml.Hymanson.core.base.ParserMinimalBase._reportUnexpectedChar(ParserMinimalBase.java:475)
JVM: at com.fasterxml.Hymanson.core.json.UTF8StreamJsonParser._handleUnexpectedValue(UTF8StreamJsonParser.java:2343)
JVM: at com.fasterxml.Hymanson.core.json.UTF8StreamJsonParser._nextTokenNotInObject(UTF8StreamJsonParser.java:818)
JVM: at com.fasterxml.Hymanson.core.json.UTF8StreamJsonParser.nextToken(UTF8StreamJsonParser.java:698)
JVM: at com.fasterxml.Hymanson.databind.ObjectMapper._initForReading(ObjectMapper.java:3031)
JVM: at com.fasterxml.Hymanson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:2978)
JVM: at com.fasterxml.Hymanson.databind.ObjectMapper.readValue(ObjectMapper.java:2158)
JVM: at org.springframework.http.converter.json.MappingHymanson2HttpMessageConverter.readJavaType(MappingHymanson2HttpMessageConverter.java:225)
```
```
import org.springframework.web.client.RestTemplate;
public static RestTemplate getRestTemplate() {
RestTemplate restTemplate = new RestTemplate();
List<HttpMessageConverter<?>> messageConverters = new ArrayList<HttpMessageConverter<?>>();
MappingHymanson2HttpMessageConverter converter = new MappingHymanson2HttpMessageConverter();
List<MediaType> mediaTypes = new ArrayList<MediaType>();
mediaTypes.add(MediaType.TEXT_HTML);
mediaTypes.add(MediaType.APPLICATION_JSON);
converter.setSupportedMediaTypes(mediaTypes);
messageConverters.add(converter);
messageConverters.add(new StringHttpMessageConverter());
restTemplate.setMessageConverters(messageConverters);
return restTemplate;
}
//The call is here
ResponseEntity<BargeType[]> responseEntity = getRestTemplate().getForEntity(url+"/bargetype", BargeType[].class);
```
I checked the URL being passed in with my browser and I am getting back JSON. I copy and pasted the response into json lint and validated it successfully.
我检查了使用浏览器传入的 URL，然后返回 JSON。我将响应复制并粘贴到 json lint 中并成功验证。
I'm guessing there is an error returned because the error messsage has '<' in the exception.
我猜有一个错误返回，因为错误消息在异常中有“<”。
My questions are:
我的问题是：
1) Is there a better pattern to use RestTemplate?
1) 有没有更好的模式来使用 RestTemplate？
2) Is there a way to get the http error?
2）有没有办法得到http错误？
Updated 5/3/2018 Using Fiddler Daisy recommended, the GET Response Header using Browser on my workstation (however, app is running on server).
2018 年 5 月 3 日更新推荐使用 Fiddler Daisy，GET Response Header 在我的工作站上使用浏览器（但是，应用程序正在服务器上运行）。
HTTP/1.1 200 OK
Server: Lotus-Domino
Date: Thu, 03 May 2018 15:28:23 GMT
Connection: close
Content-Type: text/html; charset=UTF-8
[{"contract":xxxx,"customer":".....
采纳答案by stwissel
An XPage by default returns its result as text/htmldespite of what you do in the XPage. If, as the example suggest, you compute JSON (and not HTML looking like JSON), you can overwrite the returned header to application/json. Then add a plugin to Chromethat renders the JSON in the browser so you can check.
text/html无论您在 XPage 中执行什么操作，XPage 都会默认返回其结果。如果，如示例所示，您计算 JSON（而不是看起来像 JSON 的 HTML），您可以将返回的标头覆盖为application/json. 然后向 Chrome添加一个插件，在浏览器中呈现 JSON，以便您进行检查。
What is very well possible: If a server calls Domino, how does it authenticate? When you have session based authentication and it fails, you won't get a 401 back, but the HTML based input form for username/password (Try the page in your browser using an anonymous window).
很有可能：如果服务器调用 Domino，它如何进行身份验证？当您使用基于会话的身份验证并且失败时，您将不会得到 401，而是返回基于 HTML 的用户名/密码输入表单（使用匿名窗口尝试浏览器中的页面）。
In the Domino configuration you can specify that a URL can use basic authentication besides the session. Then your server can send https://user:[email protected]/yourdb.nsf/somexpage.xspto get the result.
在 Domino 配置中，您可以指定 URL 可以使用除会话之外的基本身份验证。然后您的服务器可以发送https://user:[email protected]/yourdb.nsf/somexpage.xsp来获取结果。
So first check: Does your server use a user/pass and does it have sufficient access.
所以首先检查：您的服务器是否使用用户/通行证并且它是否有足够的访问权限。
回答by Paul A M C
Rest Assured failed to parse specified format
Rest Assured 无法解析指定的格式
Example for XML, you need to use as
XML 示例，您需要将其用作
response.as(ClassName.class, ObjectMapperType.JAXB);
Other predefined object mappers that can be used with REST Assured as below:
可与 REST Assured 一起使用的其他预定义对象映射器如下：
public enum ObjectMapperType {
HymanSON_2, HymanSON_1, GSON, JAXB
}
