Javascript jquery 中的“Uncaught SyntaxError: Unexpected identifier”错误
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"Uncaught SyntaxError: Unexpected identifier" error in jquery
提问by PitaJ
I'm making a new jQuery plugin for drawing lines on a page. The problem is that I can't figure out what's going on here, when I run the script, in Chrome it says:
我正在制作一个新的 jQuery 插件，用于在页面上绘制线条。问题是我无法弄清楚这里发生了什么，当我运行脚本时，在 Chrome 中它说：
"Uncaught SyntaxError: Unexpected identifier"
on the 8th to last line (the one that reads: $.line();).
在第 8 行到最后一行（读作：）$.line();。
The whole code:
整个代码：
(function( $ ) {
$.fn.line = function(coordinates) {
var bothpoints;
$.fn.line.draw = function() {
var lineColor = $('#lineRegion').attr('lineColor');
if (!lineColor) {
var colors = ['black', 'blue', 'green', 'red', 'yellow', 'purple', 'magenta', 'cyan'];
$('img.line').each(function () {
colors.splice(colors.indexOf($(this).css('color')), 1);
});
var lineColor = colors[0];
}
var data = $.line.data(),
width = Math.abs(data[0] - data[2]),
height = Math.abs(data[1] - data[3]);
if (data[0] >> data[2]) {
var lineleft = data[2];
} else {
var lineleft = data[0];
}
if (data[1] >> data[3]) {
var linetop = data[1];
} else {
var linetop = data[3];
}
$('body').append('<img class="line" src="/lines/line-'+lineColor+'.png" style="position:absolute;top:'+linetop+';left:'+lineleft+';width:'+width+'px;height:'+height+'px;color:'+lineColor+';"/>');
}
$.fn.line.data = function(coords) {
if (coords.length == 2) {
if ( ! $('#line').data('point1') ) {
$('#line').data('point1', {x: coords[0], y: coords[1]});
bothpoints = false;
} else {
$('#line').data('point2', {x: coords[0], y: coords[1]});
bothpoints = true;
}
$.line.draw();
} else if (coords == 1) {
$('#line').data('point1', false);
bothpoints = false;
} else if (coords == 2) {
$('#line').data('point2', false);
bothpoints = false;
} else if (!coords) {
return [$('#line').data('point1').x, $('#line').data('point1').y, $('#line').data('point2').x, $('#line').data('point2').y];
}
}
$.fn.line.point = function() {
if (!($.line.data().length == 4)) {
var _posY = posy, _posX = posx;
$('body').append('<div class="point" style="position:absolute; top:' + _posY + 'px; left:' + _posX + 'px;"></div>');
$.line.data([_posX, _posY]);
if (bothpoints == true) {
$.line.draw();
}
}
}
$.fn.line.unpoint = function() {
this.hide('fast');
if ($.line.data()[0] == this.offset()['left'] && $.line.data[1] == this.offset()['top']) {
$.line.data(1);
} else {
$.line.data(2);
}
$.line.erase();
}
$.fn.line.erase = function(total) {
if (total == true) {
$('img.line').hide('fast');
$('div.point').hide('fast');
$.line.data(1);
$.line.data(2);
} else {
$('img.line').hide('fast');
}
}
if ( coordinates.length == 4) {
$.line.data([coordinates[0], coordinates[1]]);
$.line.data([coordinates[2], coordinates[3]]);
$.line.draw();
}
};
var posx, posy;
$(document).ready(function(){
$(document).on('mousemove', function(e) {
if (!e) var e = window.event;
if (e.pageX || e.pageY) {
posx = e.pageX;
posy = e.pageY;
}
else if (e.clientX || e.clientY) {
posx = e.clientX + document.body.scrollLeft
+ document.documentElement.scrollLeft;
posy = e.clientY + document.body.scrollTop
+ document.documentElement.scrollTop;
}
}
$.line();
$('head').append('<meta id="line" />');
$('#lineRegion').click( $.line.point() );
$('.point').click( $.line.unpoint() );
$('.lineEraser').click( $.line.erase(true) );
}
})( jQuery );
回答by Gabe
You start an in-line function: $(document).on('mousemove', function(e) {and never finish the statement after it. Before the line with the error, you need });instead of just }.
你启动一个内联函数：$(document).on('mousemove', function(e) {并且永远不会完成它后面的语句。在出现错误的行之前，您需要});而不仅仅是}.
