postgresql laravel属于有条件的
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laravel belongstomany with condition
提问by Dariel Pratama
i have the following model.
我有以下型号。
class Training extends \Eloquent {
// Add your validation rules here
public static $rules = [
'name' => 'required',
'city' => 'required',
'province' => 'required',
'budget_year' => 'required|integer',
's_date' => 'required|date',
'e_date' => 'required|date'
];
// Don't forget to fill this array
protected $fillable = [
'name',
'city',
'province',
'budget_year',
's_date',
'e_date'
];
public function material(){
return $this->hasMany('Material');
}
public function budget(){
return $this->belongsToMany('Budget')->withPivot('amount');
}
public function budgetById($training_id){
$this->belongsToMany('Budget')->where('training_id', '=', $training_id)->get();
}
}
when i debug the budgetByIdmethod using DB::getQueryLog, the query is as follow
当我调试budgetById使用的方法时DB::getQueryLog，查询如下
select budgets.*,
budget_training.training_id as pivot_training_id,
budget_training.budget_id as pivot_budget_id
from budgets inner join budget_training on budgets.id = budget_training.budget_id
where budget_training.training_id is null and training_id='6'
which return 0 rows, but when i try to modify the query and run it in pgadmin, the following script works well.
它返回 0 行，但是当我尝试修改查询并在 pgadmin 中运行它时，以下脚本运行良好。
select budgets.*,
budget_training.training_id as pivot_training_id,
budget_training.budget_id as pivot_budget_id
from budgets inner join budget_training on budgets.id = budget_training.budget_id
where budget_training.training_id='6'
notice i remove training_id is null andfrom laravel generated query. what is wrong with my budgetByIdmethod?
注意我training_id is null and从 Laravel 生成的查询中删除。我的budgetById方法有什么问题？
回答by The Alpha
You have called get()and didn't use returnhere:
您已致电get()但未return在此处使用：
public function budgetById($training_id){
// = in where is optional in this case
$this->belongsToMany('Budget')->where('training_id', '=', $training_id);
}
You should use like this:
你应该这样使用：
public function budgetById($training_id){
// = in where is optional in this case
return $this->belongsToMany('Budget')->where('training_id', '=', $training_id);
}
