php 从 Drupal 8 的链接字段中提取网址和标题？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/34499554/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Extract Url & Title from link field in Drupal 8?
提问by Kevin Wenger
I'm trying to retrieve the URLand the Titlevalues of a Link fieldin Drupal 8.
我试图检索URL和标题一个值链接字段中的Drupal 8。
In my custom controller, I retrieve the nodes with:
在我的自定义控制器中，我使用以下命令检索节点：
$storage = \Drupal::entityManager()->getStorage('node');
$nids = $storage->getQuery()
->condition('type', 'partners')
->condition('status', 1)
->execute();
$partners = $storage->loadMultiple($nids);
When I loop throught all my nodes, to preprocess vars I'll give to my view, I would like to retrieve the URLand the Title.
当我遍历所有节点时，为了预处理我将提供给我的视图的变量，我想检索URL和Title。
foreach ($partners as $key => $partner) {
$variables['partners'][] = array(
'image' => $partner->field_logo->entity->url(),
'url' => $partner->field_link->value, // Can't retrieve values of link field
);
}
Unfortunately, I don't found how to retrieve the URLand the Titleof field_link.
不幸的是，我没有找到如何检索URL和标题的FIELD_LINK。
Thanks for your help.
谢谢你的帮助。
回答by Mark Conroy
At the node level, inside your Twig template you can use:
在节点级别，您可以在 Twig 模板中使用：
{{ content.field_link.0['#url'] }}& {{ content.field_link.0['#title'] }}
{{ content.field_link.0['#url'] }}& {{ content.field_link.0['#title'] }}
For example:
例如：
<a href="{{ content.field_link.0['#url'] }}">{{ content.field_link.0['#title'] }}</a>
<a href="{{ content.field_link.0['#url'] }}">{{ content.field_link.0['#title'] }}</a>
field_linkbeing the name of the link field in question.
field_link是相关链接字段的名称。
回答by Kevin Wenger
I just found the solution ...
我刚刚找到了解决方案...
$partner->field_lien->uri // The url
$partner->field_lien->title // The title
My bad, hope it could help someone.
我的不好，希望它可以帮助某人。
回答by Greg
Just to piggyback on the above, if you have an external link,
只是为了搭载上述内容，如果您有外部链接，
$node->field_name->uri
Will give you the URL, but if it's an internal you may need to tweak a bit more:
会给你 URL，但如果它是内部的，你可能需要稍微调整一下：
use Drupal\Core\Url;
$mylink = Url::fromUri($node->field_name[0]->uri);
$mylink->toString();
回答by Benjen
You can render either the uri or text of a link field directly in the twig template. In the case of a node you can use either of the following within the twig template file (assumes the machine name of your link field is field_link):
您可以直接在树枝模板中呈现链接字段的 uri 或文本。对于节点，您可以在 twig 模板文件中使用以下任一项（假设您的链接字段的机器名称是field_link）：
{{ node.field_link.uri }}
{{ node.field_link.title }}
回答by zanvidmar
This one works for me in twig:
这个在树枝上对我有用：
content.field_link_name.0['#title'] // title
content.field_link_name.0['#url_title'] // url value
*you should use: "Separate link text and URL" widget in display
*您应该使用：显示中的“单独的链接文本和 URL”小部件
回答by Vishal Rao
Updated for Drupal 8
为 Drupal 8 更新
To get the url all you need to do is:
要获取 url，您需要做的就是：
{{ content.field_link_name[0]['#url'] }}
To get the link text:
要获取链接文本：
{{ content.field_link_name[0]['#title'] }}
回答by mel-miller
If you want to do this in a field template instead of a node template do this:
如果要在字段模板而不是节点模板中执行此操作，请执行以下操作：
{% for item in items %}
{{ item.content['#url'] }}
{{ item.content['#title'] }}
{% endfor %}
Alternately, if this is not a multi-value field you can just do this instead:
或者，如果这不是多值字段，您可以改为执行以下操作：
{{ items|first.content['#url'] }}
{{ items|first.content['#title'] }}
回答by Kiwad
If you're doing it in a preprocess, I'd suggest to base your code on LinkSeparateFormatter.php. It shows the idea on how to get the title from the link field. Here's a way to do it.
如果您在预处理中执行此操作，我建议将您的代码基于 LinkSeparateFormatter.php。它展示了如何从链接字段获取标题的想法。这是一种方法。
use Drupal\Component\Utility\Unicode;
//...
$field_link = $entity->field_link->first();
$link_url = $field_link->getUrl();
$link_data = $field_link->toArray();
// If you want to truncate the url
$link_title = Unicode::truncate($link_url->toString(), 40, FALSE, TRUE);
if(!empty($link_data['title'])){
// You could truncate here as well
$link_title = $link_data['title'];
}
$variables['content'] = [
'#type' => 'link',
'#url' => $link_url,
'#title' => $link_title,
];
回答by Arti Prasad
I am doing this link separation for ECK fields and this solution really helped me. I have updated the code for ECK fields for apply inline style in twig file like this:
我正在为 ECK 字段做这个链接分离，这个解决方案真的帮助了我。我已经更新了 ECK 字段的代码，以便在 twig 文件中应用内联样式，如下所示：
<a style="color: {{ entity.field_link_color[0] }};" href="{{ entity.field_link[0]['#url'] }}"> {{ entity.field_link[0]['#title'] }} </a>
<a style="color: {{ entity.field_link_color[0] }};" href="{{ entity.field_link[0]['#url'] }}"> {{ entity.field_link[0]['#title'] }} </a>
To get url:{{ entity.field_link[0]['#url'] }}
获取网址：{{ entity.field_link[0]['#url'] }}
To get link title: {{ entity.field_link[0]['#title'] }}
获取链接标题： {{ entity.field_link[0]['#title'] }}
回答by Debasish
After rendering a block if you want to access the link field used in it then you can use like this $render['field_target_url']['#items']->uri inside node preprocess hook.
渲染块后，如果您想访问其中使用的链接字段，则可以像这样使用 $render['field_target_url']['#items']->uri 内部节点预处理钩子。
