Java 如何创建获取 4 个数字并返回最大数字的 max 方法？
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How to create max method that gets 4 numbers and returns the maximum number?
提问by YoAv
I'm trying to build a method that would get 4 numbers and returns the maximum number of them.
我正在尝试构建一个可以获取 4 个数字并返回它们的最大数量的方法。
I tried to write this code that gets 4 numbers but this not working:
我试图编写这段获得 4 个数字的代码，但这不起作用：
Input and output:
输入输出：
double a = Math.max(10, 5, 4, 3);
System.out.println(a);
public static int max(int a, int b, int c, int d) {
if (a > b && a > c && a > d)
return a;
if (b > a && b > c && b > d)
return b;
if (c > a && c > b && c > d)
return c;
if (d > b && d > c && d > a)
return d;
}
采纳答案by Patrick Hofman
I would simplify this by introducing a variable max:
我会通过引入一个变量来简化这个max：
public static int max(int a, int b, int c, int d) {
int max = a;
if (b > max)
max = b;
if (c > max)
max = c;
if (d > max)
max = d;
return max;
}
You could also use Math.max, as suggestedby fast snail, but since this seems to be homework, I would prefer the algorithmic solution.
你也可以使用Math.max，如建议通过快速的蜗牛，但因为这似乎是家庭作业，我宁愿算法的解决方案。
Math.max(Math.max(a,b),Math.max(c,d))
回答by SMA
Try Math.maxlike below:
尝试Math.max如下：
return Math.max(Math.max(a, b), Math.max(c, d));
回答by PARITOSH THAPLIYAL
if (c > a && c > b && c > d)
return d;
here you are returning d instead of c.
在这里，您返回的是 d 而不是 c。
回答by Erich Kitzmueller
One more way to do it...
另一种方法来做到这一点......
public static int max(int a, int b, int c, int d) {
if (a > b && a > c && a > d)
return a;
if (b > c && b > d)
return b;
if (c > d)
return c;
return d;
}
回答by BarrySW19
You could always use a method like this which will work as you wanted for any number of integers:
你总是可以使用这样的方法，它可以为任意数量的整数工作：
public static Integer max(Integer... vals) {
return new TreeSet<>(Arrays.asList(vals)).last();
}
Call, for example, as:
例如，调用如下：
System.out.println(max(10, 5, 17, 4, 3));
回答by maimArt
public static Integer max(Integer... values)
{
Integer maxValue = null
for(Integer value : values)
if(maxValue == null || maxValue < value)
maxValue = value;
return maxValue;
}
回答by Ar maj
public static int max(int a, int b, int c, int d){
return (a>b && a>c && a>d? a: b>c && b>d? b: c>d? c:d);
}
回答by coja
public static int max(int a, int b, int c, int d) {
int tmp1 = a > b ? a : b;
int tmp2 = c > d ? c : d;
return tmp1 > tmp2 ? tmp1 : tmp2;
}
回答by shifu
public static int max(Integer... vals) {
return Collections.max(Arrays.asList(vals));
}
回答by Karthik Bose
private int max(int... p)
{
int max = 0;
for (int i : p) {
max = i > max ? i : max;
}
return max;
}
