线程“main”中的异常java.lang.NumberFormatException：对于输入字符串：“S”
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Exception in thread "main" java.lang.NumberFormatException: For input string: "S"
提问by Mattias S
I get this error when I try to use Integer.parseInt() with a single char.
当我尝试使用带有单个字符的 Integer.parseInt() 时出现此错误。
String s = "s";
System.out.println((char) Integer.parseInt(s));
Is what gives me the error is this:
是什么给了我错误是这样的：
Exception in thread "main" java.lang.NumberFormatException: For input string: "S"
采纳答案by Joni
The letter Sis not a number. Did you mean to write the number 5?
字母S不是数字。你是想写数字5吗？
String s = "5";
System.out.println((char) Integer.parseInt(s));
Or did you mean to print the ASCII or Unicode value of the character S?
或者你的意思是打印字符的 ASCII 或 Unicode 值S？
char s = 's';
System.out.println((int) s);
回答by darxtrix
yes of course.. Integer.parseInt can make the integer representation of only numeric strings.Try:
是的当然.. Integer.parseInt 可以使仅数字字符串的整数表示。尝试：
String s="98"
字符串 s="98"
回答by Oleg Pyzhcov
parseInt(String s)is used to convert integers in string form like "42"to value they represent in decimal. Use String.charAt(0)if you want first character.
parseInt(String s)用于将字符串形式的整数转换"42"为它们以十进制表示的值。String.charAt(0)如果您想要第一个字符，请使用。
回答by mawia
To parse an string to a number you must have valid number into the string.
要将字符串解析为数字，您必须在字符串中包含有效数字。
Here your S is not a number.
这里你的 S 不是数字。
String s = "s"; System.out.println((char) Integer.parseInt(s));
It should be something like this:
它应该是这样的：
String s = "100";//or whatever integer you want to parse.
System.out.println((char) Integer.parseInt(s));
回答by Gyanendra Dwivedi
it is nothing to do with single or multichar value. A simple test of this is that, if you remove the ' (quotes) from the value, would you find a Integer?
它与单字符或多字符值无关。对此的一个简单测试是，如果您从值中删除 '（引号），您会找到一个整数吗？
If no, the Integer.parseiInt()is bound to fail.
如果不是，Integer.parseiInt()则必然会失败。
I would recomend you to go for really quick and short tutorial located at http://www.tutorialspoint.com/java/number_parseint.htm
我会建议你去位于http://www.tutorialspoint.com/java/number_parseint.htm 的非常快速和简短的教程
