Java 在数组中替换
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Replace in Array
提问by Mac135
im trying make one replace in string from a array but this dont work
我正在尝试从数组中替换字符串，但这不起作用
dna[i].replace('T', 'C');
and with this way work?
并以这种方式工作？
"ATCTA".replace('T', 'C');
why dont work with array, how i can use use a replace in array[]
为什么不使用数组，我如何使用数组中的替换[]
Now i have other problem, i want use various replaces in original string, how i can mahe this????
现在我有其他问题，我想在原始字符串中使用各种替换，我该怎么办？？？？
采纳答案by Andreas Dolk
String dna[] = {"ATCTA"};
int i = 0;
dna[i] = dna[i].replace('T', 'C');
System.out.println(dna[i]);
This works as expected. Double check your code if you follow a similiar pattern.
这按预期工作。如果您遵循类似的模式，请仔细检查您的代码。
You may have expected, that dna[i].replace('T', 'C');changes the content of the cell dna[i]directly. This is not the case, the String will not be changed, replacewill return a new String where the char has been replaced. It's necessary to assign the result of the replaceoperation to a variable.
您可能已经预料到，这dna[i].replace('T', 'C');会dna[i]直接更改单元格的内容。情况并非如此，字符串不会改变，replace将返回一个新的字符串，其中字符已被替换。有必要将replace操作的结果分配给一个变量。
To answer your last comment:
要回答您的最后一条评论：
Strings are immutable - you can't change a single char inside a String object. All operations on Strings (substring, replace, '+', ...) always create new Strings.
字符串是不可变的 - 您不能更改 String 对象内的单个字符。对字符串的所有操作（子字符串、替换、'+'、...）总是创建新的字符串。
A way to make more than one replace is like this:
一种进行多次替换的方法是这样的：
dna[i] = dna[i].replace('T', 'C').replace('A', 'S');
回答by jjnguy
An array is just a data structure that holds data. It doesn't support any operations on that data. You need to write the algorithms to work on the data yourself.
数组只是一种保存数据的数据结构。它不支持对该数据进行任何操作。您需要编写算法来自己处理数据。
A Stringis basically a char array with some methods that you can call on that. The replace()method is one of them.
AString基本上是一个 char 数组，其中包含一些您可以调用的方法。该replace()方法是其中之一。
The method you want would look something like this:
你想要的方法看起来像这样：
static void replace(char[] arr, char find, char replace) {
for (int i = 0; i < arr.length; i++) {
if (arr[i] == find) {
arr[i] = replace;
return;
}
}
}
You would then call it like so:
然后你可以这样称呼它：
replace(dna, 'T', 'C');
That would replace the first instance of Tin the array with a C.
这将用 a 替换T数组中的第一个实例C。
