Scala：将 Seq 传递给 var-args 函数
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Scala: pass Seq to var-args functions
提问by David Crawshaw
Given a function that takes a variable number of arguments, e.g.
给定一个带有可变数量参数的函数，例如
def foo(os: String*) =
println(os.toList)
How can I pass a sequence of arguments to the function? I would like to write:
如何将参数序列传递给函数？我想写：
val args = Seq("hi", "there")
foo(args)
Obviously, this does not work.
显然，这行不通。
回答by Joa Ebert
foo(args:_*)does the trick. Instead of applying the sequence as one single argument, each element in the sequence will be used as an argument.
foo(args:_*)诀窍。不是将序列作为单个参数应用，而是将序列中的每个元素用作参数。
