bash 通过 grepping qstat 输出并将 jobid 发送到 qdel 来删除作业？
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delete jobs by grepping qstat output and sending jobid to qdel?
提问by David LeBauer
I am using PBS job scheduler on my cluster, and I would like to delete jobs older than a certain date using qdel; alternatively it would be sufficient to be able to sort the results of qstatby date.
我在我的集群上使用 PBS 作业调度程序，我想使用qdel;删除早于某个日期的作业；或者，能够qstat按日期对结果进行排序就足够了。
qstatgives this output:
qstat给出这个输出：
job-ID prior name user state submit/start at queue slots ja-task-ID
-----------------------------------------------------------------------------------------------------------------
326539 0.50500 run user r 01/06/2011 11:13:34 [email protected] 1
326594 0.50500 run user r 01/06/2011 11:13:34 [email protected] 1
and I can delete jobs with qdel:
我可以删除作业qdel：
qdel 326539
and the jobs I want to delete can be located using grep:
可以使用grep以下方法找到我要删除的作业：
qstat > foo; grep 01/06 foo
my current work around is to paste the output from above into a spreadsheet, sort by job-ID, and then qdel {min..max},
我目前的工作是将上面的输出粘贴到电子表格中，按作业 ID 排序，然后qdel {min..max}，
Can I combine these steps into a single command?
我可以将这些步骤合并为一个命令吗？
Assistance appreciated.
帮助表示赞赏。
采纳答案by SiegeX
awk
awk
qstat | awk ' ~ "01/06" {cmd="qdel " ; system(cmd); close(cmd)}'
Bash
重击
#!/bin/bash
match="01/06"
while read job; do
set -- $job
if [[ =~ $match ]]; then
qdel ""
fi
done < <(qstat)
If you want to do a dry-run, then change qdel "$1"to echo qdel "$1"to see what it would have done.
如果您想进行试运行，请更改qdel "$1"为echo qdel "$1"以查看它会做什么。
