在本教程中，我们将在各种标准的基础上看到如何对元组列表进行排序。

让我们在例子的帮助下，假设我们有以下元组列表：

#tuple having structure (name,age,salary)
l=[("Mohan",21,20000),("John",19,10000),("hyman",23,25000),("igi",20,5000),("Martin",27,7000)]

现在我们想根据年龄和年龄的年龄对元组进行排序列表，是元组中的第一个索引。
我们可以使用以下代码来根据年龄对元组列表进行排序。

#tuple having structure (name,age,salary)
l=[("Mohan",21,20000),("John",19,10000),("hyman",23,25000),("igi",20,5000),("Martin",27,7000)]
sortList=sorted(l, key=lambda x: x[1])
print("Sorted list of tuples based on age:",sortList)

输出：

Sorted list of tuples based on age: [('John', 19, 10000), ('igi', 20, 5000), ('Mohan', 21, 20000), ('hyman', 23, 25000), ('Martin', 27, 7000)]

如果要按降序排序，那么我们只需要添加Reversed = True如下所示。

#tuple having structure (name,age,salary)
l=[("Mohan",21,20000),("John",19,10000),("hyman",23,25000),("igi",20,5000),("Martin",27,7000)]
sortList=sorted(l, key=lambda x: x[1],reverse=True)
print("Sorted list of tuples based on age in descending order:",sortList)

输出：

Sorted list of tuples based on age: [('Martin', 27, 7000), ('hyman', 23, 25000), ('Mohan', 21, 20000), ('igi', 20, 5000), ('John', 19, 10000)]

让我们在薪水的基础上排序元组列表。

#tuple having structure (name,age,salary)
l=[("Mohan",21,20000),("John",19,10000),("hyman",23,25000),("igi",20,5000),("Martin",27,7000)]
#Sorting by salary(2nd index of tuple)
sortList=sorted(l, key=lambda x:x[2])
print("Sorted list of tuples based on salary:",sortList)

输出：

Sorted list of tuples based on age in descending order: [('igi', 20, 5000), ('Martin', 27, 7000), ('John', 19, 10000), ('Mohan', 21, 20000), ('hyman', 23, 25000)]