C语言 字符数组到浮点数转换

character array to floating point conversion

提问by Vaibhav Sundriyal

I am trying to convert the output buffer(character array) of the code below to floating point format for further calculations. Can anybody tell me how to do it.

我正在尝试将下面代码的输出缓冲区（字符数组）转换为浮点格式以进行进一步计算。谁能告诉我怎么做。

#include "usbtmc.h"
#include <errno.h>
#include <stdio.h>
#include <fcntl.h>
#include <unistd.h>
#include <stdlib.h>
#include <getopt.h>
#include <inttypes.h>
#include <sys/types.h>
#include <pthread.h>

int main() 
{

    int myfile;
    char buffer[4000];

    int actual;

    myfile=open("/dev/usbtmc1",O_RDWR);
    if(myfile>0)
    {
        system("echo MEAS:VOLT:AC?>/dev/usbtmc1");
        actual=read(myfile,buffer,4000);

        buffer[actual] = 0;
        printf("Response = \n %s\n",buffer);

        close(myfile);
    }


    return 0;
}

The sample output for this code is

此代码的示例输出是

Response = +1.29273072E-04

响应 = +1.29273072E-04

回答by Grijesh Chauhan

You may have two ways:

你可能有两种方法：

1. using double atof(const char* str)

   float f;
   f = (float)atof(buffer);
   printf("%f",f); // here you can use f
   

2. using int sscanf( const char * s, const char * format, ...)

   float f;
   sscanf(buffer,"%f",&f);
   printf("%f",f); // here you can use f
   

1. 使用double atof(const char* str)

   float f;
   f = (float)atof(buffer);
   printf("%f",f); // here you can use f
   

2. 使用int sscanf( const char * s, const char * 格式, ...)

   float f;
   sscanf(buffer,"%f",&f);
   printf("%f",f); // here you can use f