bash 命令 - 在 `ls` 中使用 for i 和 if 语句

bash command - using for i in `ls` with an if statement

提问by sputn1ck

I'm trying to clean up some directories that are all named in sequence 1001, 1002, 1003 and I can't seem to get this script to work to delete directories with a value less than a number

我正在尝试清理一些以 1001、1002、1003 顺序命名的目录，但我似乎无法使用此脚本来删除值小于数字的目录

Contents of the DIR

目录的内容

1000 1001 1002 1003 1004 1005 1006 1007 1008 1009 1010 1011 1012 1013 1014

My command

我的命令

for i in `ls`; do if (( $i < 1011 )) then echo rm $i -rf; done

but I get the error

但我得到了错误

-su: syntax error near unexpected token `then'

Can anyone point me in the right direction?

任何人都可以指出我正确的方向吗？

回答by Andreas Florath

for i in *; do [ $i -lt 1011 ] && rm -fr $i; done

does the job.

做这项工作。

Note: this really removes the files and does not just print the remove commands.

注意：这确实会删除文件，而不仅仅是打印删除命令。

回答by Spencer Rathbun

Looping over ls is bad, as explained here. Instead, use find, like so:

循环 ls 是不好的，正如这里所解释的。相反，使用查找，如下所示：

find . -regex '\./10[01][0-9]' -exec echo rm '{}' -rf \;

回答by Bela Vizer

try

尝试

for i in `ls`; do if [ $i -lt 1011 ]; then echo rm $i -rf; fi; done

edited

已编辑

回答by gustaf r

do

that's the reason.

这就是原因。

for i in `ls` ; do whatever ; done