laravel 响应内容必须是实现 __toString() 的字符串或对象是什么，给定的“对象”。意思是为什么我只能在遥控器上得到它？
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What does The Response content must be a string or object implementing __toString(), "object" given. mean and why do I only get it on the remote?
提问by Himmators
I'm running an app on PagodaBox. Locally it works fine, but when I push it to pagoda, I get the following error:
我正在 PagodaBox 上运行一个应用程序。在本地它工作正常，但是当我将其推送到宝塔时，出现以下错误：
The Response content must be a string or object implementing __toString(), "object" given.
响应内容必须是字符串或实现 __toString() 的对象，给定的“对象”。
Here is the route:
这是路线：
Route::get('tweets/{q}', function($q)
{
return Twitter::getSearch(array('q' => $q, 'count' => 5, 'lang' => 'sv', 'result_type' => 'recent'));
});
Other routes work fine. What does this error mean and what could cause this error?
其他路线工作正常。这个错误是什么意思，什么可能导致这个错误？
回答by DinkoM
Do this to see what is returned.
执行此操作以查看返回的内容。
dd(Twitter::getSearch(array('q' => $q, 'count' => 5, 'lang' => 'sv', 'result_type' => 'recent')));
You have to return View class which has __toString() method or if it's ajax request then something like Response::json($data);
您必须返回具有 __toString() 方法的 View 类，或者如果它是 ajax 请求，则返回类似 Response::json($data); 的内容。
回答by Juan Manuel Garcia Carmona
create the following function
创建以下函数
function utf8_encode_deep(&$input) {
if (is_string($input)) {
$input = utf8_encode($input);
} else if (is_array($input)) {
foreach ($input as &$value) {
self::utf8_encode_deep($value);
}
unset($value);
} else if (is_object($input)) {
$vars = array_keys(get_object_vars($input));
foreach ($vars as $var) {
utf8_encode_deep($input->$var);
}
}
try to do the following
尝试执行以下操作
$response = Twitter::getSearch(array('q' => $q, 'count' => 5, 'lang' => 'sv', 'result_type' => 'recent'));
utf8_encode_deep($response);
return response;
