Linux 如何获取文件的完整路径？
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How to get full path of a file?
提问by Jean
Is there an easy way I can print the full path of file.txt?
有没有一种简单的方法可以打印 的完整路径file.txt？
file.txt = /nfs/an/disks/jj/home/dir/file.txt
The <command>
这 <command>
dir> <command> file.txt
should print
应该打印
/nfs/an/disks/jj/home/dir/file.txt
回答by jcomeau_ictx
I knowthere's an easier way that this, but darned if I can find it...
我知道有一种更简单的方法，但如果我能找到它，那就太糟糕了......
jcomeau@intrepid:~$ python -c 'import os; print(os.path.abspath("cat.wav"))'
/home/jcomeau/cat.wav
jcomeau@intrepid:~$ ls $PWD/cat.wav
/home/jcomeau/cat.wav
回答by ZeRemz
The following usually does the trick:
以下通常可以解决问题：
echo $(cd $(dirname "") && pwd -P)/$(basename "")
回答by Andrew_1510
Beside "readlink -f" , another commonly used command:
除了 "readlink -f" ，另一个常用命令：
$find /the/long/path/but/I/can/use/TAB/to/auto/it/to/ -name myfile /the/long/path/but/I/can/use/TAB/to/auto/it/to/myfile $
$find /the/long/path/but/I/can/use/TAB/to/auto/it/to/ -name myfile /the/long/path/but/I/can/use/TAB/to/auto/it/to/myfile $
This also give the full path and file name at console
这也给出了控制台的完整路径和文件名
Off-topic: This method just gives relativelinks, not absolute. The readlink -fcommand is the right one.
题外话：这个方法只给出相对链接，而不是绝对链接。该readlink -f命令是正确的。
回答by Ackq
In a similar scenario, I'm launching a cshell script from some other location. For setting the correct absolute path of the script so that it runs in the designated directory only, I'm using the following code:
在类似的情况下，我从其他位置启动 cshell 脚本。为了设置脚本的正确绝对路径，使其仅在指定目录中运行，我使用以下代码：
set script_dir = `pwd`/`dirname function absolute_path { echo "$PWD/"; }
alias ap="absolute_path"
`
$0stores the exact string how the script was executed.
$0存储脚本如何执行的确切字符串。
For e.g. if the script was launched like this: $> ../../test/test.csh,
$script_dirwill contain /home/abc/sandbox/v1/../../test
例如，如果脚本是这样启动的：$> ../../test/test.csh,
$script_dir将包含/home/abc/sandbox/v1/../../test
回答by Roman Rhrn Nesterov
You can save this in your shell.rcor just put in console
您可以将其保存在您的shell.rc或只是放在控制台中
ap somefile.txt
example:
例子：
/home/user/somefile.txt
will output
会输出
find $PWD -type f | grep "filename"
回答by Anshul Gupta
find $PWD -type f -name "*filename*"
or
或者
find / -name file.txt
回答by user2618464
This will give you absolute path of the file:
这将为您提供文件的绝对路径：
% pwd
/Users/adamatan/bins/scripts/fpn
% ls
LICENSE README.md fpn.py
% fpn *
/Users/adamatan/bins/scripts/fpn/LICENSE
/Users/adamatan/bins/scripts/fpn/README.md
/Users/adamatan/bins/scripts/fpn/fpn.py
回答by Adam Matan
You could use the fpn (full path name)script:
您可以使用fpn（完整路径名）脚本：
find / -samefile file.txt -print
fpnis not a standard Linux package, but it's a free and open github projectand you could set it up in a minute.
fpn不是一个标准的 Linux 包，但它是一个免费和开放的 github 项目，你可以在一分钟内设置它。
回答by wildplasser
find /bin -samefile /bin/gunzip -ls
Will find all the links to the file with the same inode numberas file.txt
将找到与file.txt具有相同inode 编号的文件的所有链接
adding a -xdevflag will avoid findto cross device boundaries ("mount points"). (But this will probably cause nothing to be found if the finddoes not start at a directory on the same device as file.txt)
添加-xdev标志将避免find跨越设备边界（“挂载点”）。（但是，如果find不在与 相同设备上的目录中启动，则这可能不会导致找不到任何内容file.txt）
Do note that findcan report multiple paths for a single filesystem object, because an Inode can be linked by more than one directory entry, possibly even using different names. For instance:
请注意，find可以为单个文件系统对象报告多个路径，因为一个 Inode 可以由多个目录条目链接，甚至可能使用不同的名称。例如：
12845178 4 -rwxr-xr-x 2 root root 2251 feb 9 2012 /bin/uncompress
12845178 4 -rwxr-xr-x 2 root root 2251 feb 9 2012 /bin/gunzip
Will output:
将输出：
##代码##