Bash - 如何获取当前文件夹中文件夹的名称？
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Bash - How to get the name a folder inside the current folder?
提问by mike23
Let's say my script is running inside a folder, and in this folder is anther folder with a name that can change each time I run the script. How can I find the name of that folder ?
假设我的脚本在一个文件夹中运行，并且在这个文件夹中有另一个文件夹，其名称可以在每次运行脚本时更改。我怎样才能找到那个文件夹的名字？
Edit:
编辑：
As an example, let's say my script is running in the folder /testfolder, which is known and does not change.
例如，假设我的脚本正在文件夹 中运行，该文件夹/testfolder是已知且不会更改的。
In /testfolderthere is another folder : /testfolder/randomfolder, which is unknown and can change.
在/testfolder还有另一个文件夹 : /testfolder/randomfolder，这是未知的并且可以更改。
How do I find the name of /randomfolder?
我如何找到 的名字/randomfolder？
I hope it's clearer, sorry for the confusion.
我希望它更清楚，对混淆感到抱歉。
回答by Paused until further notice.
dirs=(/testfolder/*/)
dirswill be an array containing the names of each directory that is a direct subdirectory of /testfolder.
dirs将是一个包含每个目录名称的数组，该目录是/testfolder.
If there's only one, you can access it like this:
如果只有一个，您可以像这样访问它：
echo "$dirs"
or
或者
echo "${dirs[0]}"
If there is more than one and you want to iterate over them:
如果有多个并且您想遍历它们：
for dir in "${dirs[@]}"
do
echo "$dir"
done
回答by glenn Hymanman
Assuming there is exactly one subdirectory:
假设只有一个子目录：
dir=$(find . -mindepth 1 -maxdepth 1 -type d)
If you don't have GNU find, then
如果你没有找到 GNU，那么
for f in *; do [[ -d "$f" ]] && { dir=$f; break; }; done
