PHP：从返回的时间值中删除秒数
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PHP: remove seconds off of returned time value
提问by Plummer
I need to remove the seconds off of a returned time value. I get
我需要从返回的时间值中删除秒数。我得到
12:00:00
I want
我想要
12:00pm
I tried using date()but it kept returning the time as 1:00am for everything.
我尝试使用，date()但它一直将所有时间返回为凌晨 1:00。
echo date('g:ia', $timestamp);
回答by Sean
Use strtotime()-
使用strtotime()-
echo date('g:ia', strtotime($timestamp));
The date()function - string date ( string $format [, int $timestamp = time() ] )- where $timestampis to be an integer Unix timestamp.
的date()功能- string date ( string $format [, int $timestamp = time() ] )-其中，$timestamp是为整数Unix时间戳。
回答by JvO
$timestamp = $timestamp - ($timestamp % 60);
In other words, use the modulo function to substract the number of seconds in the current minute from the time.
换句话说，使用模函数从时间中减去当前分钟的秒数。
Somtimes, simpler is better (and a lot more efficient than strtotime).
有时，越简单越好（而且比 strtotime 效率更高）。
回答by Luca C.
If you only need to remove seconds (not PM needed), you can use both MYSQL or php:
如果您只需要删除秒（不需要 PM），则可以同时使用 MYSQL 或 php：
MYSQL:
MYSQL：
SELECT SUBSTRING(SEC_TO_TIME(seconds), 1, 5);
PHP:
PHP：
$cleantime=substr($time,0,-3);
both will strip off seconds and keep hours and minutes
两者都将去除秒并保留小时和分钟
thanks to Jahanzeb for enhancing the PHP version to support also > 99 hours
感谢 Jahanzeb 增强 PHP 版本以支持 > 99 小时
回答by Kermit
Have you tried strtotime()?
你试过strtotime()吗？
echo date( 'g:ia', strtotime("12:00:00") );
