如何在java中的特定字符后修剪字符串
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How to trim a string after a specific character in java
提问by user2430771
I have a string variable in java having value:
我在java中有一个字符串变量具有值：
String result="34.1 -118.33\n<!--ABCDEFG-->";
I want my final string to contain the value:
我希望我的最终字符串包含值：
String result="34.1 -118.33";
How can I do this? I'm new to java programming language.
我怎样才能做到这一点？我是java编程语言的新手。
Thanks,
谢谢，
采纳答案by alfasin
You can use:
您可以使用：
result = result.split("\n")[0];
回答by arshajii
Assuming you just want everything before \n(or any other literal string/char), you should use indexOf()with substring():
假设您只想要之前的所有内容\n（或任何其他文字字符串/字符），您应该使用indexOf()with substring()：
result = result.substring(0, result.indexOf('\n'));
If you want to extract the portion before a certain regular expression, you can use split():
如果要提取某个正则表达式之前的部分，可以使用split()：
result = result.split(regex, 2)[0];
String result = "34.1 -118.33\n<!--ABCDEFG-->";
System.out.println(result.substring(0, result.indexOf('\n')));
System.out.println(result.split("\n", 2)[0]);
34.1 -118.33 34.1 -118.33
(Obviously \nisn't a meaningful regular expression, I just used it to demonstrate that the second approach also works.)
（显然\n不是一个有意义的正则表达式，我只是用它来证明第二种方法也有效。）
回答by óscar López
Try this:
尝试这个：
String result = "34.1 -118.33\n<!--ABCDEFG-->";
result = result.substring(0, result.indexOf("\n"));
回答by gparyani
Use a Scannerand pass in the delimiter and the original string:
使用 aScanner并传入分隔符和原始字符串：
result = new Scanner(result).useDelimiter("\n").next();
回答by Pshemo
How about
怎么样
Scanner scanner = new Scanner(result);
String line = scanner.nextLine();//will contain 34.1 -118.33
回答by Bohemian
Use regex:
使用正则表达式：
result = result.replaceAll("\n.*", "");
replaceAll()uses regex to find its target, which I have replaced with "nothing" - effectively deleting the target.
replaceAll()使用正则表达式查找其目标，我已将其替换为“无” - 有效地删除了目标。
The target I've specified by the regex \n.*means "the newline char and everything after"
我由正则表达式指定的目标\n.*意味着“换行符和之后的所有内容”
回答by Abstract
You could use result = result.replaceAll("\n","");or
你可以使用 result = result.replaceAll("\n","");或
String[] split = result.split("\n");
回答by samlewis
There are many good answers, but I would use StringUtilsfrom commons-lang. I find StringUtils.substringBefore()more readable than the alternatives:
有很多很好的答案，但我会使用StringUtils来自commons-lang。我发现StringUtils.substringBefore()比替代方案更具可读性：
String result = StringUtils.substringBefore("34.1 -118.33\n<!--ABCDEFG-->", "\n");
回答by irshad
you can use StringTokenizer:
你可以使用StringTokenizer：
StringTokenizer st = new StringTokenizer("34.1 -118.33\n<!--ABCDEFG-->", "\n");
System.out.println(st.nextToken());
output:
输出：
34.1 -118.33
