bash 对于 `ls` 中的名称和带空格的文件名
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for name in `ls` and filenames with spaces
提问by Yola
next code doesnt work because of spaces in file names, How to fix?
由于文件名中有空格，下一个代码不起作用，如何解决？
IFS = '\n'
for name in `ls `
do
number=`echo "$name" | grep -o "[0-9]\{1,2\}"`
if [[ ! -z "$number" ]]; then
mv "$name" "./$number"
fi
done
回答by fge
Just don't use command substitution: use for name in *.
只是不要使用命令替换：使用for name in *.
回答by ugoren
Replace
代替
for name in `ls`
with:
和：
ls | while read name
Notice: bash variable scoping is awful. If you change a variable inside the loop, it won't take effect outside the loop (in my version it won't, in your version it will). In this example, it doesn't matter.
注意：bash 变量范围很糟糕。如果您在循环内更改变量，则它不会在循环外生效（在我的版本中不会，在您的版本中会）。在这个例子中，这无关紧要。
Notice 2: This works for file names with spaces, but fails for some other strange but valid file names. See Charles Duffy's comment below.
注意 2：这适用于带有空格的文件名，但对于其他一些奇怪但有效的文件名无效。请参阅下面的查尔斯·达菲 (Charles Duffy) 的评论。
回答by jaypal singh
Looks like two potential issues:
看起来有两个潜在的问题：
First, the IFS variable and it's assignment should not have space in them. Instead of
首先，IFS 变量及其赋值中不应有空格。代替
IFS = '\n'it should be IFS=$'\n'
IFS = '\n'它应该是 IFS=$'\n'
Secondly, for name in lswill cause issues with filename having spacesand newlines. If you just wish to handle filenamewith spacesthen do something like this
其次，for name in ls会导致文件名具有spaces和 的问题newlines。如果你只是想处理filename与spaces再这样做
for name in *
for name in *
I don't understand the significance of the line
我不明白这条线的意义
number=`echo "$name" | grep -o "[0-9]\{1,2\}"`
This will give you numbers found in filename with spacesin new lines. May be that's what you want.
这将为您提供filename with spaces在new lines. 可能这就是你想要的。
