Java：通过 Parse.com REST API 将日期对象作为 JSONObject 发送
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Java: Send Date Object as JSONObject through Parse.com REST API
提问by Koolstr
I am trying to create a new object in my Parse.com database through Parse's REST API, using an HttpsUrlConnection. Their REST API only accepts JSON. I have gotten everything to work, where the database would accept the new object entry - except for when I attempt to include a Date field. When I do pass in a Date, the server rejects the object entirely.
我正在尝试使用 HttpsUrlConnection 通过 Parse 的 REST API 在我的 Parse.com 数据库中创建一个新对象。他们的 REST API 只接受 JSON。我已经让一切正常工作，数据库将接受新的对象条目 - 除非我尝试包含日期字段。当我传入一个日期时，服务器会完全拒绝该对象。
I found this in their documentation this description for how to add a Date field in an object when using the REST API:
我在他们的文档中找到了有关如何在使用 REST API 时在对象中添加日期字段的描述：
The Parse mobile client libraries also support dates, binary data, and relational data. In the REST API, these values are encoded as JSON hashes with the __type field set to indicate their type, so you can read or write these fields if you use the correct encoding.
The Date type contains a field iso which contains a UTC timestamp stored in ISO 8601 format with millisecond precision: YYYY-MM-DDTHH:MM:SS.MMMZ.
Parse 移动客户端库还支持日期、二进制数据和关系数据。在 REST API 中，这些值被编码为 JSON 散列，并设置了 __type 字段以指示它们的类型，因此如果您使用正确的编码，则可以读取或写入这些字段。
日期类型包含一个字段 iso，其中包含以 ISO 8601 格式存储的 UTC 时间戳，精度为毫秒：YYYY-MM-DDTHH:MM:SS.MMMZ。
{
"__type": "Date",
"iso": "2011-08-21T18:02:52.249Z"
}
So if I want to create a new object and pass it to the database, I am assuming I need to create another JSONObject and pass it over in its corresponding field. However, when I tried that, it still rejected it. Below is my attempt at adding the Date object as a parameter to pass over, stored in its own JSONObject. What am I doing wrong? What is the right way of sendign a Date object in JSON, based on their docs?
因此，如果我想创建一个新对象并将其传递给数据库，我假设我需要创建另一个 JSONObject 并将其传递到其相应的字段中。但是，当我尝试这样做时，它仍然拒绝了它。下面是我尝试将 Date 对象添加为要传递的参数，并存储在它自己的 JSONObject 中。我究竟做错了什么？根据他们的文档，在 JSON 中发送 Date 对象的正确方法是什么？
//datePicked is a Calendar object
Date sendTime = datePicked.getTime();
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
formatter.setTimeZone(TimeZone.getTimeZone("UTC"));
String sendTimeInUTC = formatter.format(sendTime);
//Storing the Date object as a JSONObject, as specified
JSONObject dateAsObj = new JSONObject();
dateAsObj.put("__type", "Date");
dateAsObj.put("iso", sendTimeInUTC);
//jsonParam is the JSONObject that is being sent over to Parse's REST API
jsonParam.put("sendTime", dateAsObj);
Here is the full function which makes the http request, for context and reference:
这是发出 http 请求的完整函数，用于上下文和参考：
private void runHttpRequest(final String emailAddress, final String password,
String[] recipients, final String title, final String message) throws MalformedURLException {
//Stores email in Parse DB, from Java servlet
String url = "https://api.parse.com/1/classes/Email";
URL obj = new URL(url);
HttpsURLConnection con = null;
try {
con = (HttpsURLConnection) obj.openConnection();
} catch (IOException e) {
System.out.println("Failed to connect to http link");
e.printStackTrace();
}
//add request header
try {
con.setRequestMethod("POST");
} catch (ProtocolException e) {
System.out.println("Failed to set to POST");
e.printStackTrace();
}
con.setRequestProperty("X-Parse-Application-Id", "*****************");
con.setRequestProperty("X-Parse-REST-API-Key", "*******************");
con.setRequestProperty("Content-Type", "application/json");
JSONObject jsonParam = new JSONObject();
jsonParam.put("username", "******");
jsonParam.put("emailID", 1);
jsonParam.put("universalID", "******");
Gson converter = new Gson();
String recipientsInJson = converter.toJson(recipients);
jsonParam.put("to", recipientsInJson);
jsonParam.put("from", emailAddress);
jsonParam.put("title", title);
jsonParam.put("body", message);
Date sendTime = datePicked.getTime();
//jsonParam.put("sendTime", sendTime);
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
formatter.setTimeZone(TimeZone.getTimeZone("UTC"));
String sendTimeInUTC = formatter.format(sendTime);
System.out.println("UTC time" + sendTimeInUTC);
JSONObject dateAsObj = new JSONObject();
dateAsObj.put("__type", "Date");
dateAsObj.put("iso", sendTimeInUTC);
System.out.println(dateAsObj.toString());
jsonParam.put("sendTime", dateAsObj);
String urlParameters = jsonParam.toString();
// Send POST request
con.setDoOutput(true);
DataOutputStream wr = null;
try {
wr = new DataOutputStream(con.getOutputStream());
} catch (IOException e1) {
System.out.println("Failed to get output stream");
e1.printStackTrace();
}
try {
wr.writeBytes(urlParameters);
} catch (IOException e) {
System.out.println("Failed to connect to send over Parse object as parameter");
e.printStackTrace();
}
try {
wr.flush();
} catch (IOException e) {
e.printStackTrace();
}
try {
wr.close();
} catch (IOException e) {
System.out.println("Failed to connect to close datastream connection");
e.printStackTrace();
}
int responseCode = 0;
try {
responseCode = con.getResponseCode();
} catch (IOException e) {
System.out.println("Failed to connect to get response code");
e.printStackTrace();
}
System.out.println("\nSending 'POST' request to URL : " + url);
System.out.println("Post parameters : " + urlParameters);
System.out.println("Response Code : " + responseCode);
BufferedReader in = null;
try {
in = new BufferedReader(
new InputStreamReader(con.getInputStream()));
} catch (IOException e) {
System.out.println("Failed to get input stream");
e.printStackTrace();
}
String inputLine;
StringBuffer response = new StringBuffer();
try {
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
} catch (IOException e) {
System.out.println("Failed to read line");
e.printStackTrace();
}
try {
in.close();
} catch (IOException e) {
System.out.println("Failed to close input stream");
e.printStackTrace();
}
//print result
System.out.println(response.toString());
}
Any help or input would be appreciated.
任何帮助或输入将不胜感激。
采纳答案by Jon Skeet
Your format doesn't match the one they've required. For example:
您的格式与他们要求的格式不匹配。例如：
Theirs: 2011-08-21T18:02:52.249Z
Yours: 2011-08-21 18:02:52.249
You're missing the Tand the Z.
你错过了T和Z。
So try changing your format to:
因此，请尝试将格式更改为：
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
To be honest, I'd be surprised if this weren't handled automatically though - have you tried just dateAsObj.put("iso", sendTime)?
说实话，如果这不是自动处理的，我会感到惊讶 - 你试过dateAsObj.put("iso", sendTime)吗？
回答by Girish Sharma
Standard Date Object is not stored in Parse. You have to set it as a JSON Object with "__type": "Date"and "iso": Date_String_you_want_to_set.
with the date string formatted as below:
标准日期对象不存储在 Parse 中。你必须将其设置为JSON对象与"__type": "Date"和"iso": Date_String_you_want_to_set。日期字符串格式如下：
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
