jQuery - :not() 中的多个选择器？
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jQuery - Multiple Selectors in a :not()?
提问by Charlie Sheather
I cant seem to get the following working:
我似乎无法得到以下工作：
$('input:not([type=radio][type=checkbox])').live('click', function() {
alert("You haven't clicked a radio or checkbox!");
});
Have tried a few different syntax's, can anyone help me out on this one.
尝试了几种不同的语法，谁能帮我解决这个问题。
Cheers
Charlie
干杯
查理
回答by Frédéric Hamidi
You're confusing the multiple selectorwith the multiple attribute selector. You should write:
$("input:not([type=radio], [type=checkbox])");
The multiple attribute selector [type=radio][type=checkbox]matches the elements whose typeattributes are equal to bothradioandcheckbox, which cannot happen in this universe.
多个属性选择器[type=radio][type=checkbox]，其中的元素相匹配type的属性是等于两个radio和checkbox，不能在这个宇宙中发生。
回答by darkliquid
The syntax inside the not()is identical to the normal selector syntax, so if you want to match things that are not either of those things, you use a selector in the not that would match both (since essentially you're negating the selector). How do you do that? The same way you apply styles to multiple selectors at once in CSS, with a comma, as so:
里面的语法not()与普通选择器语法相同，所以如果你想匹配不是这些东西中的任何一个的东西，你可以在 not 中使用一个选择器来匹配两者（因为本质上你是在否定选择器）。你是怎样做的？与在 CSS 中一次将样式应用于多个选择器的方式相同，使用逗号，如下所示：
$('input:not([type=radio],[type=checkbox])')
That should select all inputs the not [type=radio]and not [type=checkbox]
那应该选择所有输入 not[type=radio]和 not[type=checkbox]
回答by Junaid Anwar
You can also exclude items like this:
您还可以排除这样的项目：
$('input').not('[type=radio], [type=checkbox]').live('click', function() {
alert("You haven't clicked a radio or checkbox!");
});
